2 years ago

State the factoring rule for difference of two squares a2-b2

Mathematics

1 answer:

ludmilkaskok [199]2 years ago

4 0

<h3>Answer: a^2 - b^2 = (a-b)(a+b)</h3>

The order of the factors does not matter.

So (a-b)(a+b) is the same as (a+b)(a-b)

This is known as the difference of squares factoring rule.

You can FOIL out (a-b)(a+b) and you'd get a^2+ab-ab-b^2. Note how the ab terms cancel leaving us with a^2-b^2. This confirms we have the correct factorization.

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Two factors of -48 have a difference of 19 the factor with the greater absolute value is positive what is the sum of the factors

MA_775_DIABLO [31]

1). Two factors of -48 => x * y = -48

=> the absolute values of the two numbers may be:

48 and 1

24 and 2

16 and 3

12 and 4

6 and 8

2). Have a differencie of 19 = > x - y = 19

That makes that the numbers be + 16 and - 3

Because (+16) * (-3) = - 48

And +16 - (-3) = +16 + 3 = 19.

3) The sum of the factors is +16 + (-3) = 16 - 3 = 13.

So the answer is the option C. 13.

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