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charle [14.2K]
2 years ago
5

State the factoring rule for difference of two squares a2-b2

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
4 0
<h3>Answer:  a^2 - b^2 = (a-b)(a+b)</h3>

The order of the factors does not matter.

So (a-b)(a+b) is the same as (a+b)(a-b)

This is known as the difference of squares factoring rule.

You can FOIL out (a-b)(a+b) and you'd get a^2+ab-ab-b^2. Note how the ab terms cancel leaving us with a^2-b^2. This confirms we have the correct factorization.

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Find out the  length of OP .

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As given

In △JKL, ​ JO=44 in. ​

Now as shown in the diagram.

JP , MK, NL be the median of the △JKL and intresection of the JP , MK, NL be O .

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x = 22 in

Thus the length of the OP IS 22 in .







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