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3 years ago

Write the numeral of twelve Arab sixty core

Mathematics

2 answers:

ivolga24 [154]3 years ago

6 0

Answer:

12600000000

Step-by-step explanation:

write the numeral of twelve Arab sixty core

The numeral of twelve Arab sixty core is

=> 12600000000

hope it is helpful to you

vovikov84 [41]3 years ago

3 0

Step-by-step explanation:

the numeral from is 12600000000

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Solve each of the following equations. Show its solution set on a number line. Check your answers. 5−p+6=−8

olasank [31]

Add 8 to 5 and 6 on the left side of the equation. Put p on the right side. Answer is 19=p

8 0

3 years ago

Read 2 more answers

Find each product or quotient.

solniwko [45]

-38(-3) = 114

-72/(-12) = 6

-9 x 23 = -207

-150/5 = -30

564 / -4 = -141

<h3>Solution:</h3>

Given that, we have to find each product or quotient

-38(-3)

It is a product, so we have to find product value

$-38(-3)=38 \times 3=114$

-72 / (-12)

It is division, so we have to find the quotient

$\frac{-72}{-12}=\frac{72}{12}=6$

-9 x 23

It is a product, so we have to find product value

$-9 \times 23=-207$

- 150 / 5

It is division, so we have to find quotient

$\frac{-150}{5}=-30$

564 / -4

It is division, so we have to find the quotient

$\frac{564}{-4}=-141$

3 0

4 years ago

45/111 expressed as a percent rounded to the nearest whole is

elena55 [62]

Answer:

0.4054, or 0.004054%

Step-by-step explanation:

Just by dividing the two numbers, you get an approximate answer of 0.4054, and percent just means moving the decimal 2 spots to the left, so our final answer is 0.004054%.

3 0

3 years ago

Does anyone know how to solve this math equation?

garik1379 [7]

Answer:

x = 8; y = -6

Step-by-step explanation:

We have a system of equations.

$\dfrac{3(x - 2)}{2} - \dfrac{y - 2}{4} = 11$

$\dfrac{2(x + 2)}{5} - \dfrac{y}{3} = 6$

First, let's multiply both sides of each equation by the LCM of both denominators of that equation to eliminate all denominators.

First equation:

$8 \times \dfrac{3(x - 2)}{2} - 8 \times \dfrac{y - 2}{4} = 8 \times 11$

$12(x - 2) - 2(y - 2) = 88$

$12x - 24 - 2y + 4 = 88$

$12x - 2y = 108$

$6x - y = 54$

The equation above is the simplified first equation.

Second equation:

$\dfrac{2(x + 2)}{5} - \dfrac{y}{3} = 6$

$15 \times \dfrac{2(x + 2)}{5} - 15 \times \dfrac{y}{3} = 15 \times 6$

$6(x + 2) - 5y = 90$

$6x + 12 - 5y = 90$

$6x - 5y = 78$

The equation above is the simplified second equation.

The simplified system of equations is:

$6x - y = 54$

$6x - 5y = 78$

The x term of both equations is 6x. If we multiply both sides of the second equation by -1 to get a first term of -6x, then when it is added to 6x, the x terms are eliminated.

Now we rewrite the first simplified equation as it is. Below it, we write the second equation multiplied by -1 on both sides. Then we add the equations.

$6x - y = 54$

$-6x + 5y = -78$