Answer:
Advance ticket costs $25
Same-day ticket costs $20
Step-by-step explanation:
Let x = the price of one the advance ticket.
Let y = the price of one same-day ticket.
The combined cost of one advance ticket and one same-day ticket is $ 45. This means
x + y = 45 - - - - - - 1
For one performance, 30 advance tickets and 20 same-day tickets were sold. The total amount paid for the tickets was $ 1150. This means
30x + 20y = 1150 - - - - - - - - -2
From equation 1, x = 45- y
Put x = 45- y in equation 2
30( 45-y) + 20y = 1150
1350 - 30y + 20y = 1150
-10y = 1150-1350
-10y = -200
y = 200/10 = $20
x = 45-y
x =45-20= $25
Advance ticket costs $25
Same-day ticket costs $20
85% of 17 is 14.45, so the whole number would be 14.
hope this helps!
Answer:
so we get as,
let, y = 2 - 9i
so the absolute value is |y|
so we get as,
|y| =
2-9i
so the absolute value is |y|
|y|=√
2 to the 2nd power plus 9 to the second power
so we get as,
|y|=
√81+4=√85
so the value is √85
Example:
|
−
2
−
i
|
=
√
5
Explanation:
Absolute value of a complex number a
+
i
b is written as |
a
+
i
b
| and its value as √a
2
+
b
2
.
Hence, absolute value of −
2
−
i is √
(
−
2
)
2
+
(
−
1
)
2
=
√
4
+
1
=
√
5
.
Step-by-step explanation:
Answer:
AB = 10.2m
Step-by-step explanation:
Area of triangle ADC = 52m²
AD = 12m, angle D = 102°
Area of triangle ADC = ½ × a × b × sinC
52m² = ½ × 12 × CD × sin102
52 = 6 × CD × 0.9781
CD = 52/(6× 0.9781)
CD = 52/(5.8686)
CD = 8.86m = 8.9m (1 decimal place)
Using Cosine rule to find AC = d
d² = a² + c² -2×a×d ×cosD
d² = 8.9² + 12² - 2×8.9×12× Cos102
Cos102 = -0.2079
d² = 267.61744
d = √(267.61744)
AC = d = 16.4m
For ∆ABC
Using sine rule:
a/sinA = b/sinB
AB/sin46 = AC/sin120
AB/0.7193 = 16.4/0.866
AB = 14.2024 ×0.7193
AB = 10.2m (1 decimal place)
