Answer:
Advance tickets=$25
Same-day tickets=$15
Step-by-step explanation:
Complete question below:
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $ 40. For one performance, 25 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $1075 . What was the price of each kind of ticket?
Let
advance tickets=x
Same-day tickets=y
Combined cost of advance and same-day tickets=$40
It means,
x+y=40 Equ (1)
25 advance tickets and 30 same-day tickets=$1075
It means,
25x+30y=1075 Equ(2)
From (1)
x+y=40
x=40-y
Substitute x=40-y into (2)
25x+30y=1075
25(40-y)+30y=1075
1000-25y+30y=1075
5y=1075-1000
5y=75
Divide both sides by 5
5y/5=75/5
y=15
Recall,
x+y=40
x+15=40
x=40-15
=25
x=25
Advance tickets=$25
Same-day tickets=$15
Check
25x+30y=1075
25(25)+30(15)=1075
625+450=1075
1075=1075
Answer:
Step-by-step explanation:
(2u+3u)(u+v)-2u+3v
=2u(u+v)+3u(u+v)-2u+3v
=2u^2+2uv+3u^2+3uv-2u+3v
=5u^2+5uv-2u+3v
Answer:
c
Step-by-step explanation:
There are three answers and they are: choice 2, choice 3, choice 5
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Further Explanation:
Choice 1 is false because the intersection of the altitudes of a triangle leads to the orthocenter.
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Choice 2 is true because the three medians of any triangle always intersect at the centroid. A median is a line that goes from one vertex to the midpoint of the opposite side. In this case, we go from point E to the midpoint of side CD. The midpoint of CD is found by bisecting segment CD (see choice 5)
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Choice 3 is true. This is effectively the same as choice 5 below. The "perpendicular" aspect does not matter.
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Choice 4 is false. Following the steps mentioned here will create an altitude line (see choice 1)
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Choice 5 is true. To bisect something is to cut it in half. Let's say that point F is the midpoint of line segment CD. This means that line segment EF is one of the three medians of triangle CDE.
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edit update: I changed choice 3 from false to true
Answer:
a. (-3, 2).
b. √65
c. (x + 3)^2 + (y - 2)^2 = 65
Step-by-step explanation:
a. The center is the midpoint of the diameter PQ.
= (-10+4)/2, (-2+6)/2
= (-3, 2).
b. The radius is the distance from the center to a point on the circle.
Take the point (4, 6):
The radius = √((-3-4)^2 + (2-6)^2)
= √65.
c. The equation of the circle is:
Using the standard form
(x - h)^2 + (y - k)^2 = r^2 where (h, k) is the center and r = the radius:
it is (x - (-3)^2 + (y - 2) = 65
= (x + 3)^2 + (y - 2)^2 = 65.
