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alexira [117]
3 years ago
7

Help me please now...

Mathematics
1 answer:
kvv77 [185]3 years ago
5 0

Answer:

I cant see the picture.

Step-by-step explanation:

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Three components are randomly sampled, one at a time, from a large lot. As each component is selected, it is tested. If it passe
Angelina_Jolie [31]

Answer:

a) P(X=0)=(3C0)(0.8)^0 (1-0.8)^{3-0}=0.008

P(X=1)=(3C1)(0.8)^1 (1-0.8)^{3-1}=0.096  

E(X) = np = 3*0.8= 2.4

We expect 2.4 successes in a sample of three selected.

And the standard deviation is given by:

Sd(X)= \sigma = \sqrt{np(1-p)}=\sqrt{3*0.8*(1-0.8)}= 0.693

Represent the typical variation around the mean.

b) Y \sim Binom(n=4, p=0.8)

And we want this probability:

P(Y=3)=(4C3)(0.8)^3 (1-0.8)^{4-3}=0.4096

c) Z \sim Binom(n=4, p=0.8)

And we want this probability:

P(Z=3)=(4C3)(0.8)^3 (1-0.8)^{4-3}=0.4096

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Part a

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=3, p=0.8)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want the following probabilities

P(X=0)=(3C0)(0.8)^0 (1-0.8)^{3-0}=0.008

P(X=1)=(3C1)(0.8)^1 (1-0.8)^{3-1}=0.096

The mean is given by:

E(X) = np = 3*0.8= 2.4

We expect 2.4 successes in a sample of three selected.

And the standard deviation is given by:

Sd(X)= \sigma = \sqrt{np(1-p)}=\sqrt{3*0.8*(1-0.8)}= 0.693

Represent the typical variation around the mean.

Part b

Let Y the random variable of interest, on this case we now that:

Y \sim Binom(n=4, p=0.8)

And we want this probability:

P(Y=3)=(4C3)(0.8)^3 (1-0.8)^{4-3}=0.4096

Part c

Let Z the random variable of interest, on this case we now that:

Z \sim Binom(n=4, p=0.8)

And we want this probability:

P(Z=3)=(4C3)(0.8)^3 (1-0.8)^{4-3}=0.4096

6 0
3 years ago
100 students who are in 9th or 10th grade were asked if they participated in at least one extracurricular activity (sports, musi
Over [174]
What grade is this for?

8 0
3 years ago
Express in the form <br> n<br> :<br> 1<br> 32<br> :<br> 8
Pie

Answer: N is equal to 4

Step-by-step explanation:

4:1 = 32:8

4 0
3 years ago
How to solve it&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;&amp;
Dimas [21]

Answer:

y = 4 and x = 12

Step-by-step explanation:

Step by step explanation in the pic. Atleast the way I did it.

8 0
3 years ago
A line passes through point (5,4) and has a slope of 4/5. Find the equation of the line in slope-intercept form.
iren [92.7K]

Answer:

Y = 4/5x + 0

Step-by-step explanation:

y - 4 = 4/5(x-5)

y-4=4/5x-4

y=4/5x-4+4

7 0
3 years ago
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