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Lynna [10]
2 years ago
7

Solve for why please.

Mathematics
1 answer:
Greeley [361]2 years ago
8 0

Answer:

sin {45}^{ \circ}  =  \frac{x}{2}  \\  =  > x  = 2 \: sin {45}^{ \circ}  \\  =  > x  = 2 \times  \frac{1}{ \sqrt{2} }  \\  =  >  \green{x =  \sqrt{2} }

tan {45}^{ \circ}  =  \frac{x}{y}  =  \frac{ \sqrt{2} }{y}  \\  =  > y =   \frac{ \sqrt{2} }{tan {45}^{  \circ} }  \\  =  > y =  \frac{ \sqrt{2} }{1}  \\  =  > \pink{ y =  \sqrt{ 2 } }

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2 years ago
4
Natali [406]

The ratio of the area of ∆ABC to the area of ∆DEF is; 1:100.

<h3>What is the ratio of the area of ∆ABC to the area of ∆DEF?</h3>

Since, a major criterion for similarity and congruence of triangles is that the ratio of corresponding sides are equal.

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Read more on congruent triangles;

brainly.com/question/9217675

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