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Gnoma [55]
3 years ago
8

Need answer asap please answer quick

Mathematics
1 answer:
Alja [10]3 years ago
4 0

Answer:

d option

Step-by-step explanation:

Area of rectangle = length × breadth

Placing the values,

143 m² = length × 6.5 m

length = 143 m²/6.5 m = 22 m.

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em>

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A paint that contains 27 % green dye is mixed with a paint that contains 12 % green dye. How many gallons of each must be used t
adelina 88 [10]

Answer:

54 gallons of 26 percent green dye and then 54 gallons of 16 percent green dye

8 0
3 years ago
14 centimeters to 20 centimeters
Svetach [21]
The answer is 34 because when I add 14+20 that give me 34
5 0
3 years ago
What is the log 5x=log (2x+9)
Ray Of Light [21]
5x = 2x + 9, where 5x > 0 and 2x + 9 > 0 ;
Then, 3x = 9 ;
Then, x = 3 ;
Verify : 5 × 3 = 2 × 3 + 9 ;correct !
            5 × 3 > 0 ; correct !
            2 × 3 + 9 > 0; correct !
8 0
3 years ago
C) Three yam tubers are chosen at random from 15 tubers of which 5 are spoilt. Find the probability that, of the three chosen tu
Dmitry_Shevchenko [17]

\displaystyle\\|\Omega|=\binom{15}{3}=\dfrac{15!}{3!12!}=\dfrac{13\cdot14\cdot15}{2\cdot3}=455

a)

\displaystyle\\|A|=\binom{10}{3}=\dfrac{10!}{3!7!}=\dfrac{8\cdot9\cdot10}{2\cdot3}=120\\\\P(A)=\dfrac{120}{455}=\dfrac{24}{91}\approx26.4\%

b)

\displaystyle\\|A|=\binom{5}{3}=\dfrac{5!}{3!2!}=\dfrac{4\cdot5}{2}=10\\\\P(A)=\dfrac{10}{455}=\dfrac{2}{91}\approx2.2\%

c)

\displaystyle\\|A|=\binom{10}{2}\cdot5=\dfrac{10!}{2!8!}\cdot5=\dfrac{9\cdot10}{2}\cdot5=225\\\\P(A)=\dfrac{225}{455}=\dfrac{45}{91}\approx49.5\%

d)

A - at least one is spoilt

A' - none is spoilt

P(A)=1-P(A')

We calculated P(A') in a).

Therefore

P(A)=1-\dfrac{24}{91}=\dfrac{67}{91}\approx73.6\%

7 0
2 years ago
An experiment is given together with an event. find the (modeled) probability of each event, assuming that the coins are disting
tamaranim1 [39]
Saying that the result is "at most" one tail means that there can be zero or one tail.

Consider the sample space S, which is the set of all possible outcomes: S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}. Therefore: S = 8.

Now, consider the event space E, which is the set of successful outcomes: E = {TTT, TTH, THT, HTT}. Therefore: E = 4.

The probability will be:
p = E / S = 4 / 8 = 0.5

Hence, when <span>three coins are tossed the probability that the result is at most one tail</span> is 50%.

7 0
3 years ago
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