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3 years ago

Help please !!!!!!!!!!

Mathematics

2 answers:

anyanavicka [17]3 years ago

7 0

M=7.5!!!!!!! Hope this helps

harkovskaia [24]3 years ago

6 0

Answer:

[see below]

Step-by-step explanation:

Using the Pythagorean Theorem:

$6^2+4.5^2=m^2\\\\36+20.25=m^2\\\\5\boxe6.25=m^2\\\\\boxed{m=7.5}$

Hope this helps.

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Henry has 4 more cards than Doug. Doug has 12 cards. How many cards does Henry have?

PIT_PIT [208]

Answer: doug has 16 cards

Step-by-step explanation: 12+4=16

Give brainliest if it help :)

4 0

2 years ago

Read 2 more answers

PLEASE HELP PLEASE HELP PLEASE

WARRIOR [948]

f is given as -3

-3 is greater than -4, so use the second equation 3x-5.

replace x with -3 and calculate:

3(-3) - 5 = -9 - 5 = -14

The answer is -14.

6 0

3 years ago

Suppose that documentation lists the average sales price of a single-family home in the metropolitan Dallas/Ft. Worth/Irving, Te

Julli [10]

Answer:

"0.0373" seems to be the appropriate solution.

Step-by-step explanation:

The given values are:

n₁ = 43

n₂ = 35

$\bar{x_1}=217800$

$\bar{x_2}=204700$

$\sigma_1=30300$

$\sigma_2=33800$

Now,

The test statistic will be:

⇒ $Z=\frac{\bar{x_1}-\bar{x_2}}\sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} }$

On substituting the given values in the above formula, we get

⇒ $=\frac{217800-204400}{\sqrt{\frac{(30300)^2}{43} +\frac{(33800)^2}{35} } }$

⇒ $=\frac{217800-204400}{\sqrt{\frac{918090000}{43} +\frac{1142440000}{35} } }$

⇒ $=\frac{13400}{7347.93}$

⇒ $=1.7828$

then,

P-value will be:

= $P(Z>1.7828)$

= $0.0373$

8 0

3 years ago

Calculus= Integrate 5^x dx please break down how answer is 1/6x^6+C

aleksley [76]

Answer:

$\int\limits {5^x} \, dx = \frac{5^x}{ln\ x} + c$

Step-by-step explanation:

Note that the integral of $5^x$ is not $\frac{1}{6}x^6 + c$

The solution is as follows:

Given

$5^x$

Required

Integrate

Represent the given expression using integral notation

$\int\limits {5^x} \, dx$

This question can't be solved directly;

We'll make use of exponential rules which states;

$\int\limits {a^x} \, dx = \frac{a^x}{ln\ x} + c$

By comparing $\int\limits {5^x} \, dx$ with $\int\limits {a^x} \, dx$ ;

we can substitute 5 for a;

Hence, the expression $\int\limits {a^x} \, dx = \frac{a^x}{ln\ x} + c$ becomes

$\int\limits {5^x} \, dx = \frac{5^x}{ln\ x} + c$

-------------------------------------------------------------------------------------

However, the integral of $x^5$ is $\frac{1}{6}x^6 + c$

This is shown below:

Given that $x^5$

Applying power rule;

Power rule states that

$\int\limits{x^n}\ dx = \frac{x^{n+1}}{n+1} + c$

In this case ( $x^5$ ), n = 5;

So, $\int\limits{x^n}\ dx= \frac{x^{n+1}}{n+1} + c$

becomes

$\int\limits{x^5}\ dx = \frac{x^{5+1}}{5+1} + c$

$\int\limits{x^5}\ dx = \frac{x^{6}}{6} + c$

$\int\limits{x^5}\ dx= \frac{x^{6}}{6} + c$

4 0

3 years ago

Least to greatest -1.65/2 -7/80.9 -6/5

bagirrra123 [75]

-7,-6,-1.65,2,5,80.9 is least to greatest

3 0

4 years ago