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vekshin1
3 years ago
13

5. MRS. SANTOS RECEIVED 7% COMMISSION AFTER SELLING A

Mathematics
1 answer:
Nutka1998 [239]3 years ago
5 0

Answer:

Mrs. Santos's commission was 59,500.

Step-by-step explanation:

850,000 * 7% = 59,500

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Please help me with this on the picture
Salsk061 [2.6K]

<u>Answer:</u>

5, 7

<u>Step-by-step explanation:</u>

The mode of the numbers is 5, which means that 5 should be the most common card (highest frequency). Therefore the cards should have at least one more 5 among them.

Considering that 5 is one of the hidden cards and x is the other,

• Using the equation for the mean:

mean = \frac{sum \space\  \space\ of \space\  \space\ numbers}{number \space\  \space\ of \space\  \space\ numbers}

6 = \frac{4+5+ 9 + 5 + x}{5}

⇒ 30=23 + x

⇒ x = 7

This means 5 and 7 are the hidden cards.

3 0
2 years ago
Chaya's gross pay is $457.88 The amount of social security deducted is 6.2 of gross pay.
AfilCa [17]
6.2% of 457.88....turn percent to decimal....." of " means multiply
0.062(457.88) = 28.39 will be deducted
3 0
3 years ago
Read 2 more answers
Is it possible for a triangle to have more than one obtuse angle
Mariana [72]
No, it is not possible for a triangle to have more than one obtuse angle. Just try it out on a piece of paper... it simply doesn't work. 
Hope that helps!!
6 0
4 years ago
Read 2 more answers
The half-life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am
posledela

Step-by-step walkthrough:

a.

Well a standard half-life equation looks like this.

N = N_0 * (\frac{1}{2})^{t/p

N_0 is the starting amount of parent element.

N is the end amount of parent element

t is the time elapsed

p is a half-life decay period

We know that the starting amount is 74g, and the period for a half-life is 2.8 days.

Therefore you can create a function based off of the original equation, just sub in the values you already know.

N(t) = 74g * (\frac{1}{2})^{t/2.8days

b.

This is easy now that we have already made the function. Here we just reuse it, but plug in 2.8 days.

N(t) = 74g * (\frac{1}{2})^{t/2.8days} = N(2.8days) = 74g * (\frac{1}{2})^{2.8days/2.8days}\\= 74g * \frac{1}{2}  =  37g

c.

Now we just gotta do some algebra. Use the original function but this time, replace N(t) with 10g and solve algebraically.

10g = 74g * (\frac{1}{2})^{t/2.8days}\\\\\frac{10g}{74g} = (\frac{1}{2})^{t/2.8days}

Take the log of both sides.

log(\frac{5}{37}) = log((\frac{1}{2})^{t/2.8days})

Use the exponent rule for log laws that, log(b^x) = x*log(b)

log(\frac{5}{37}) = \frac{t}{2.8days} * log(\frac{1}{2})

\frac{log(\frac{5}{37})}{log(\frac{1}{2})}  = \frac{t}{2.8days}

2.8 * \frac{log(\frac{5}{37})}{log(\frac{1}{2})}  = t

slap that in your calculator and you get

t = 8.1 days

7 0
2 years ago
Hey I need helping with solving thank you
Marrrta [24]

Answer:

the answer to this equation is c (10)

6 0
3 years ago
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