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sergey [27]
3 years ago
6

Hey I need helping with solving thank you

Mathematics
1 answer:
Marrrta [24]3 years ago
6 0

Answer:

the answer to this equation is c (10)

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You and a group of 7 friends go out for pizza. One large pizza and 3 medium drinks cost $21.96. One large pizza and 6 medium dri
Doss [256]

Answer:

Step-by-step explanation:

x = cost of drink

y = total cost

First information: "one large pizza and 3 medium drinks cost $21.96":

3a + b = 21.96

Second information: "one large pizza and 6 medium drinks cost $30.93":

6a + b = 30.93

{3a + b = 21.96

{6a + b = 30.93

{- 3a - b = - 21.96

{6a + b = 30.93

3a = 8.97

a = 2.99

3a + b = 21.96

3•2.99 + b = 21.96

8.97 + b = 21.96

b = 21.96 - 8.97

b = 12.99

Each drink costs $2.99 and each pizza costs $12.99. The linear function rule is:

y = 2.99x + 12.99

I hope I've helped you.

8 0
3 years ago
Danni is training for a marathon. Her target speed is 25 miles per hour. She currently runs 15 miles in 1/2 and hour. Does she a
Andrews [41]
Yes because if it’s fifteen in 1/2 an hour you multiply by two she is at 30 miles an hour which surpasses her goal by five
6 0
3 years ago
What is 3 times 7 plus 5 minus 2 subtracted by 3 plus y y equals 106
Rashid [163]

Answer:

127

Step-by-step explanation:

3 x 7 + 5 - 2 -  3 + y

y = 106

3x7 = 21

21 + 5 = 26

26 - 2 = 24

24 - 3 = 21

21 + 106 = 127

6 0
3 years ago
Read 2 more answers
which graph represents a hyperbola centered at the origin, with a transverse axis of length 6 and a focus at (square root 14,0)
dem82 [27]

Answer:

Is the second graph :)in edg2020

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0
3 years ago
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