A=53/24 and B=32/10
|A| = |53/24| = 53/24
|B| = |32/10| = 32/10
AB = 53/24 * 32/10 = 1,696/240
|A| * |B| = |AB|
|53/24| * |32/10| = |1,696/240|
53/24 * 32/10 = 1,696/240
1,696/240 = 1,696/240
we will have to buy 12.
<h3>How to solve?</h3>
We know to begin with that for x candy bards:
x / 10 = 0.89; x = 8.90
We are trying to ascertain how many bars (y) must be added to this to amount to have an average of 0.80. This is represented:
(8.9 + 0.72y) / (10 + y) = 0.8
8.9 + 0.72y = 0.8 (10 + y)
8.9 + 0.72y = 8 + 0.8y
8.9 – 8 = 0.8y - 0.72y
0.9 = 0.08y
y = 0.9 / 0.08 = 11.25
However, since we cannot have a partial amount of candy bars, we will have to buy 12.
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First of all Horner
First we try with -3
1. 2. -5. -6.
-3. 3. 6
1. -1. -2. 0
To verify: -3^3+2*-3^2+15-6=0
Now we have this equation
(X+3)*(x^2 - x -2)=0
I dont know If you know sum and product but that is the easiest way so sum= 1 product = 2 so 2 and -1 are the answers.
You can do this too by this way : b^2-4ac= D
X= (-b(+or-)d^1/2)/2a
So all the zeros
2, -1 and -3
If you want more explanation, send me a comment x
Answer:
Step-by-step explanation:
isn't circumference the whole circle
and radius is the center from the outside
Answer and Step-by-step explanation:
Well, Let's refer to the attachment shall we?
The first attachment is for 
And the second attachment is for 
And the third attachment is for when you combine them together.
Now it's up to you which graph suites best? You will get your answer by referring it with my graph.
Hope this will help you!