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ziro4ka [17]
3 years ago
15

En una papelería sé adquirieron un paquete de 36 plumas este tiene un valor de 97.5 ¿Si el que compró el paquete va a vender cad

a pluma 75 centavos más cara cada pluma en cuanto La vendera?
Mathematics
1 answer:
zysi [14]3 years ago
6 0

Responder:

3,46

Explicación paso a paso:

Número de lápices comprados = 36

Costo total de los 36 lápices = 97,5

El precio unitario de cada lápiz será:

Costo total / número de lápices

97,5 / 36

= 2.708

El precio de venta por lápiz será:

Precio por lápiz + 75 céntimos

2,708 + 0,75

= 3.458

= 3,46

Por tanto, el precio de venta por lápiz será 3,46.

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jeka57 [31]
A=53/24 and B=32/10

|A| = |53/24| = 53/24
|B| = |32/10| = 32/10
AB = 53/24 * 32/10 = 1,696/240


|A| * |B| = |AB|
|53/24| * |32/10| = |1,696/240|
53/24 * 32/10 = 1,696/240
1,696/240 = 1,696/240
7 0
3 years ago
. A group of ten candy bars has an average cost of $0.89 per candy bar. How many bars must be bought at the cost of $0.72 a piec
Cloud [144]

we will have to buy 12.

<h3>How to solve?</h3>

We know to begin with that for x candy bards:

x / 10 = 0.89; x = 8.90

We are trying to ascertain how many bars (y) must be added to this to amount to have an average of 0.80.  This is represented:

(8.9 + 0.72y) / (10 + y) = 0.8

8.9 + 0.72y = 0.8 (10 + y)

8.9 + 0.72y = 8 + 0.8y

8.9 – 8 = 0.8y - 0.72y

0.9 = 0.08y

y = 0.9 / 0.08 = 11.25

However, since we cannot have a partial amount of candy bars, we will have to buy 12.

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2 years ago
What are the real zeros of f(x) = x^3 +2x^2-5x-6
netineya [11]

First of all Horner
First we try with -3
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Now we have this equation
(X+3)*(x^2 - x -2)=0

I dont know If you know sum and product but that is the easiest way so sum= 1 product = 2 so 2 and -1 are the answers.
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X= (-b(+or-)d^1/2)/2a

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If you want more explanation, send me a comment x
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3 years ago
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Answer:

Step-by-step explanation:

isn't circumference the whole circle

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Which graph represents this system?<br> first one is the system is it A.B.C or D
larisa86 [58]

Answer and Step-by-step explanation:

Well, Let's refer to the attachment shall we?

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