Answer:
The capability index for the process is 0.889
Step-by-step explanation:
Here, we want to compute the capability index for the process
To get this, we need some important parameters which we already have stated in the question
USL ( upper standard limit) = 0.048
LSL (lower standard limit) = 0.032
mean = 0.04
standard deviation = 0.003
We apply the formula as seen in the attachment below
Kindly understand that we are to calculate the Z upper and Z lower
The smallest value between the two will be our Z minimum
This is what we shall apply in the capability index formula which mathematically is;
Z minimum/3
From calculation:
Z lower = Z upper = 2.67
So therefore;
capability index = 2.67/3 = 0.889
The question is not clear because the Debbie solution lines are not visible. Nevertheless,
The correct solution for this linear equation is the following:
<span>3(x + 4) − 2 = 16
</span><span>3(x + 4) = 16 + 2
</span><span>3(x + 4) = 18
</span>(x + 4) = 18/3
(x + 4) = 6
x = 6 - 4
x = 2
Answer:
6.4
Step-by-step explanation:
formula: √(X2-X1)²+(Y2-Y1)²
hope it helps!
Answer:
(1, -1)
Step-by-step explanation:
we isolate y in the first equation
2x+y=1
-2x. -2x
y=1-2x
and now we fill y into second equation
4x-2(1-2x)=6
4x-2+4x=6
8x-2=6
+2 +2
8x=8
/8 /8
x=1
and now to find y we insert x
2(1)+y=1
2+y=1
-2. -2
y= -1
hopes this helps
To find the average speed for the whole race, you just have
to add the speed from a starting marker and the speed from the turnaround
marker going back and divide it by 2 since there are only two speeds involved.
10 m/s + 16m/s = 26 m/s / 2 = 13 m/s
Therefore, the average speed for the whole race is 13 m/s.
