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yanalaym [24]
3 years ago
11

Which shows 552 − 452 being evaluated using the difference of squares method?

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
8 0
The correct answer for the question that is being presented above is this one: "552 − 452 = (55 + 45)(55 − 45) = (100)(10) = 1,000." The equation that shows 552 − 452 being evaluated using the difference of squares method is this <span>552 − 452 = (55 + 45)(55 − 45) = (100)(10) = 1,000</span>
Marat540 [252]3 years ago
7 0

Answer:  Third Option is correct.

Step-by-step explanation:

Since we have given that

55^2-45^2

We need to evaluate using the difference of squares method:

So, here,  a = 55

b = 45

so, it becomes,

a^2-b^2=(a+b)(a-b)\\\\55^2-45^2=(55-45)(55+45)\\\\55^2-45^2=10\times 100\\\\55^2-45^2=1000

Hence, Third Option is correct.

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b. Find a 99% confidence interval for mean age of ICU patients using the facts that, in the sample, the mean is 57.55 years and
rjkz [21]

Answer:

<em>99% of confidence intervals for mean age of ICU patients</em>

<em>(53.8920 , 61.2079)</em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<em>Given sample mean </em>x^{-} = 57.55<em></em>

Given standard error is determined by

                                                             S.E =\frac{S.D}{\sqrt{n} }

<em>Given data standard error = 1.42</em>

<em>99% of confidence intervals for mean is determined by</em>

(x^{-} - Z_{0.01} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.01} \frac{S.D}{\sqrt{n} } )

Z_{\frac{\alpha }{2} } = Z_{\frac{0.01}{2} } = Z_{0.05} = 2.576

(x^{-} - 2.576 S.E , x^{-} + 2.576 S.E)

(57.55 - 2.576X 1.42 , 57.55+ 2.576 X1.42)

(53.8920 , 61.2079)

<u><em>Conclusion</em></u>:-

<em>99% of confidence intervals for mean is determined by</em>

<em>(53.8920 , 61.2079)</em>

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Answer:

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