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Mamont248 [21]
2 years ago
8

Which ordered pair is a solution of the equation y=x-2

Mathematics
2 answers:
lora16 [44]2 years ago
6 0

Answer:

A. (3 , 1)

Step-by-step explanation:

Note the placement of x and y for points:

(x , y)

Plug in the corresponding numbers for the corresponding variables:

(x , y) = (3 , 1)

y = x - 2

(1) = (3) - 2

1 = 3 - 2

1 = 1 (True).

A. (3 , 1) is your answer.

~

Inessa [10]2 years ago
5 0
answer coordinate:
A. (3,1)
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Company A.

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Company A = $450

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Assume the upper arm length of males over 20 years old in the United States is approximately Normal with mean 39.3 centimeters (
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Answer:

a) For this case we can use this:

P(X

P(X>\mu +3*\sigma)=P(X>46.5)=0.0015

So the range of lengths would be 32.1 and 46.5 since on the middle of these two values we have 1-0.0015-0.0015=0.997 or 99.7 % of the values.

b) P(X>36.9)

And using the complement rule we have:

P(X>36.9)= 1-P(X

Step-by-step explanation:

Previous concepts

The empirical rule, also known as three-sigma rule or 68-95-99.7 rule, "is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)".

Let X the random variable who represent the variable of interest.

From the problem we have the mean and the standard deviation for the random variable X. E(X)=39.3, Sd(X)=2.4

So we can assume \mu=39.3 , \sigma=2.4

On this case in order to check if the random variable X follows a normal distribution we can use the empirical rule that states the following:

• The probability of obtain values within one deviation from the mean is 0.68

• The probability of obtain values within two deviation's from the mean is 0.95

• The probability of obtain values within three deviation's from the mean is 0.997

So we have the following probabilities using this rule:

P(X    

P(X>\mu +\sigma)=P(X >41.7)=0.16  

P(X    

P(X>\mu +2*\sigma)P(X>44.1)=0.025

P(X

P(X>\mu +3*\sigma)=P(X>46.5)=0.0015

Part a

For this case we can use this:

P(X

P(X>\mu +3*\sigma)=P(X>46.5)=0.0015

So the range of lengths would be 32.1 and 46.5 since on the middle of these two values we have 1-0.0015-0.0015=0.997 or 99.7 % of the values.

Part b

For this casee we want this probability:

P(X>36.9)

And using the complement rule we have:

P(X>36.9)= 1-P(X

5 0
3 years ago
Mrs. Greenaway has decided to open a new preschool in her town. To decide whether she will have enough students to be successful
Jobisdone [24]

The answer choice which represents the group which makes up the best sample for the researcher's survey as described in the task content is; Choice A; Parents of preschool children.

<h3>Which answer choice best represents a sample for the intended survey by Mrs Greenaway's researcher?</h3>

It follows from the task content that; Mrs. Greenaway has decided to open a new preschool in her town.

The need for a researcher therefore arises from the decision to either open the preschool or not.

Consequently, in a bid to choose a sample, Mrs. Greenaway's researcher must make sure the sample chosen is from the population space.

Therefore, answer choice A represents the correct sample.

Read more on sample and population;

brainly.com/question/14320940

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Answer:

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Step-by-step explanation:

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Side: 2 * 3 / 2 = 3

4 sides = 3 * 4 = 12

Base + sides = 12 + 4 = 16

8 0
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