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2 years ago

7

Mr. Moreno drove 60 miles in March. He drove 10 times as many miles in March as he did in January. He drove 6 times as many mile

s in February as he did in January. How many miles did Mr. Moreno drive in February?

1 answer:

DENIUS [597]2 years ago

8 0

Answer:36 miles

Step-by-step explanation:

60/10=6

6x6=36

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H E L P!!!!!!!!!!!!!!!!!!!

LenaWriter [7]

Answer:

a

Step-by-step explanation:

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2 years ago

then difference between the cubes of two numbers is twice the value of the perfect square of a possitive Intiger

PSYCHO15rus [73]

There are many solutions. But what do you mean with a perfect square of a number. I thought a number IS a perfect square or not.

For example, the difference between 2² and 4² = 12, which is twice the number 6, which is √36

The difference between 2² and 6² = 32, which is twice the number 16, which is a perfect square.

So choose depending on your interpretation of the question... ;-)

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3 years ago

I need help please good people

mel-nik [20]

Answer:

x/x+3

Step-by-step explanation:

first off, we start by factorizing.

we start with the numerator taking x out making it x (x-3) / x^2 - 9

then we factorize the denominator a bit more...making it x (x-3) / (x-3) (x+3)

as you can tell there is a (x-3) on both sides. so we can cross them out.

x/x+3 is left. try it yourself again so you can understand other questions like this! I hope I could help!

3 0

2 years ago

Estimates of the number of cells in the human body vary over an order of magnitude. Indeed, the precise number varies from one

Amiraneli [1.4K]

Answer:

a) 2.00 × 10¹⁰; b) 2.00 × 10¹³

Step-by-step explanation:

a) No. of cells in 1 cm³

$\text{No. of cells} =\text{1 cm}^{3} \times\left( \dfrac{\text{1 m}}{\text{100 cm}}\right )^{3} \times \left (\dfrac{1 \, \mu \text{m} }{10^{-6}\,\text{ m}}\right )^{3} \times \dfrac{\text{1 cell}}{\text{50 $\,\mu$m}^{3}} = \mathbf{2.00 \times 10^{10}} \textbf{ cells}$

b) No. of cells in 1 L

$\text{No. of cells} = \text{1 L} \times \dfrac{\text{1000 cm}^{3}}{\text{1 L}} \times \dfrac{2 \times 10^{10} \text{ cells}}{\text{1 cm}^{3}} = \mathbf{2.00 \times 10^{13}} \textbf{ cells}$

7 0

3 years ago

In order to win a quiz contest, olga must score more than 400 points. She earns 12 points for each right answer, and loses 4 poi

Ket [755]

The inequality that represents the number of right answers (r) and wrong answers (w) Olga can give to win the contest is: $3r-w>100$

<u><em>Explanation</em></u>

Number of right answers is $r$ and number of wrong answers is $w$

Olga earns 12 points for each right answer and loses 4 points for each wrong answer.

So, total points earned for $r$ right answers $=12r$

and total points lost for $w$ wrong answers $=4w$

That means, <u>her score will be</u>: $(12r-4w)$ points.

In order to win the quiz contest, Olga must score <u>more than 400 points</u>. So, the inequality will be.......

$12r-4w>400\\ \\4(3r-w)>400\\ \\ 3r-w>100$

4 0

2 years ago