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damaskus [11]
2 years ago
5

one endpoint of a line segment is (1,2) and the midpoint of the midpoint of the segment is (-1,4) what is the other end point ?

Mathematics
1 answer:
pishuonlain [190]2 years ago
3 0
The other end point is (-3,6)
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3) Solve each equation using the quadratic formula. Show<br> a. x2 – 3x – 10 = 0
Naya [18.7K]

Answer:

<h2>x = -2 or x = 5</h2>

Step-by-step explanation:

The quadratic formula of a quadratic equation

ax^2+bx+c=0\\\\\text{If}\ b^2-4ac>0\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

\text{If}\ b^2-4ac=0\ \text{then the equation has one solution}\ x=\dfrac{-b}{2a}

\text{If}\ b^2-4ac

We have:

x^2-3x-10=0\to a=1,\ b=-3,\ c=-10\\\\b^2-4ac=(-3)^2-4(1)(-10)=9+40=49>0\\\\x=\dfrac{-(-3)\pm\sqrt{49}}{2(1)}=\dfrac{3\pm7}{2}\\\\x=\dfrac{3-7}{2}=\dfrac{-4}{2}=-2\\or\\x=\dfrac{3+7}{2}=\dfrac{10}{2}=5

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=0.4" id="TexFormula1" title="0.4" alt="0.4" align="absmiddle" class="latex-formula"><br>what f
andrey2020 [161]

Answer:

0.4 is equal to the fraction <u>2/5</u>

Step-by-step explanation:

0.4 = 4/10

= 2/5

Thus, 0.4 = 2/5

Hope it helps.

8 0
3 years ago
Read 2 more answers
I am useless plz help
Alex777 [14]

Answer: your answer is 195

Step-by-step explanation:

4 0
3 years ago
Solve the system by elimination 1: x+5y-4z=-10, 2x-y+5z=-9, 2x-10y-5z=0 .. . 2. Solve the system by substitution: 2x-y+z=-4, z=5
Kryger [21]
1 )
1st and 2nd equation (multiply 1st by -2 ):
-2x - 10 y + 8 z = 20
2 x -  y    + 5 z = -9
---------------------------
       - 11 y + 13 z = 11  /  * ( -20 )
1st and 3rd:
- 2 x - 10 y + 8 z = 20
   2 x - 10 y - 5 z = 0
-----------------------------
         - 20 x + 3 z = 20  /  * 11
        ----------------------------------
         220 y - 260 z = -220
        - 220 y + 33 z = 220
        ------------------------------
                       z = 0,      y = -1,        x = - 5
2 )  
       2 x - y + 5 = -4
       - 2 x + 3 y - 5 = - 10
       Substitution: y = 2 x + 9
       - 2 x + 3(2 x + 9 ) = -5
        4 x = - 32,          x = -8,    y = -7,   z = 5
3 )
      x + y + z = 11
   1.5 x+3 y +1.5 z = 21
      x = 2 y
   ------------------------
      3 y + z = 11  / * (-2)
      6 y + 1.5 z = 21
    ------------------------
     - 6 y - 2 z = -22
       6 y + 1.5 z = 21
      ------------------------
                 -0.5 z = -1,           z = 2,   y = 3,   z = 6
Answer: the store used 6 pounds of peanuts, 3 pounds of almonds and 2 pounds of raisins. 
           
8 0
3 years ago
If g (x) = 1/x then [g (x+h) - g (x)] /h
lys-0071 [83]

Answer:

\dfrac{-1}{x(x+h)}, h\ne 0

Step-by-step explanation:

If g(x) = \dfrac{1}{x}, then g(x+h) = \dfrac{1}{x+h}. It follows that

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

  \begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

  = \dfrac{-1}{x(x+h)}, h\ne 0

5 0
3 years ago
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