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Anna [14]
3 years ago
15

Find n=100 for #1 a. 1 b. 10 c. 5 d. 100

Mathematics
1 answer:
Finger [1]3 years ago
7 0
The answer is D.


..................
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Find area of parallelogram multiple choice
alina1380 [7]

In ∆ABD

\\ \sf\longmapsto Area=\dfrac{1}{2}bh=\dfrac{1}{2}(7\times 4)

In ∆BCD

\\ \sf\longmapsto Area=\dfrac{1}{2}(7\times 4)

Now

IN PARALLELOGRAM ABCD

\\ \sf\longmapsto Area=\dfrac{1}{2}(7\times 4)+\dfrac{1}{2}(7\times 4)

Option A

4 0
2 years ago
What is the solution set of 4x^2-36= 0?<br><br> (-3)<br> (3)<br> (-3,3)
ololo11 [35]

Answer:

(-3, 3).

Step-by-step explanation:

4x^2-36= 0

4x^2 = 36    Taking square roots of both sides:

2x = +/- 6

x = +/- 3.

6 0
3 years ago
Read 2 more answers
Prove that the median to the hypotenuse of a right triangle is half the hypotenuse,
REY [17]

Answer:

D. 2

Step-by-step explanation:

M(0,2b)

N(2a,0)

Then the midpoint P coordinates are

P\left(\dfrac{2a+0}{2},\dfrac{0+2b}{2}\right)\Rightarrow P(a,b)

Use distance formula to find OP and MN:

OP=\sqrt{(a-0)^2+(b-0)^2}=\sqrt{a^2+b^2}\\ \\MN=\sqrt{(2a-0)^2+(2b-0)^2}=\sqrt{4a^2+4b^2}=2\sqrt{a^2+b^2}

So,

MN=2OP

or

OP=1/2 MN

Click to let others know, how helpful is it

7 0
2 years ago
Find the area of each.<br> 11)<br> 14 in<br> Help plz
stiks02 [169]

Answer:

The area would be 153.86

Step-by-step explanation:

Since the diameter is 14, the radius would be 7.

The area is pi times the radius squared.

7 squared is 49.

If your using 3.14 for pi, then its 3.14 times 49.

That gives you 153.86.

7 0
2 years ago
Read 2 more answers
Can you explain triangle congruence therom
Nesterboy [21]
There are five ways to find if two triangles are congruent: SSS, SAS, ASA, AAS and HL.
SSS (side, side, side) SSS stands for "side, side, side" and means that we have two triangles with all three sides equal. ...
SAS (side, angle, side) ...
ASA (angle, side, angle) ...
AAS (angle, angle, side) ...
HL (hypotenuse, leg)

Please visit this site for further information:
http://www.mathsisfun.com/geometry/triangles-congruent-finding.html
4 0
3 years ago
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