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Anna [14]
3 years ago
15

Find n=100 for #1 a. 1 b. 10 c. 5 d. 100

Mathematics
1 answer:
Finger [1]3 years ago
7 0
The answer is D.


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What is the cost of 1 shirt if I have 3 shirts and 2 scarves totaling $94?
Pepsi [2]

Let x be the cost of 1 shirt and y be the cost of 1 scarf.

Since, 3 shirts and 2 scarves cost $94, we have,

3x + 2y = 94

Since the number of unknowns is greater than the number of equations (2 > 1), the above system has infinitely many solutions.

If t is the cost of 1 scarf, then

3x + 2t = 94

3x = 94 - 2t

x = \frac{94-2t}{3}

For different values for t, we will get different values for x.

Set t = 2.

Then, x = \frac{94-2(2)}{3}

= \frac{94-4}{3}

= \frac{90}{3}

= 30

So, if the cost of 1 scarf is $2, then the cost of 1 shirt is $30.


6 0
3 years ago
What is the probability that a value falls in the interval μ ± 2σ, that computes the probability P(-2 < Z < 2). Round to f
bija089 [108]

Answer:

0.9544    

Step-by-step explanation:

P(-2 < Z < 2) means that Z has mean 0 and standard deviation 2.

P(−2 < Z < 2) = F(2) - F(-2)

Using the Z - table,

F(2) = 0.9772

and F(-2) = 0.0228

Thus,

P(−2 < Z < 2) = 0.9772 - 0.0228 = 0.9544

This means that data within two standard deviation is 95%.

8 0
3 years ago
Create a equation for this exponential function
Evgen [1.6K]

Answer:

f(X) 70x49

Step-by-step explanation:

5 0
2 years ago
What is the approximate length of the radius of a circle with a circumference of 63 inches?
Sergeeva-Olga [200]

Answer: 63/2π

Step-by-step explanation: C=πd  

                                             63=πd

                                             D=63/π

r=1/2d

1/2×63/π=<u>63/2π</u>

       

5 0
3 years ago
SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council
fgiga [73]

Answer:

0.91517

Step-by-step explanation:

Given that SAT scores (out of 1600) are distributed normally with a mean of 1100 and a standard deviation of 200. Suppose a school council awards a certificate of excellence to all students who score at least 1350 on the SAT, and suppose we pick one of the recognized students at random.

Let A - the event passing in SAT with atleast 1500

B - getting award i.e getting atleast 1350

Required probability = P(B/A)

= P(X>1500)/P(X>1350)

X is N (1100, 200)

Corresponding Z score = \frac{x-1100}{200}

P(X>1500)/P(X>1350)\\= \frac{P(Z>2)}{P(Z>1.25} \\=\frac{0.89435}{0.97725} \\=0.91517

4 0
3 years ago
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