Anyone wanna attempt to help me

Mathematics

1 answer:

ArbitrLikvidat [17]3 years ago

7 0

Answer:

t=57, u=31, v=92

Step-by-step explanation:

So we know that 180= 5x+2+2x+9+8x+4 which simplifies to 180 = 15x+15. Subtract 15 from both sides to get 165=15x and then divide by 15 to get 11=x. NOw we can plug this into the three angles as x so t = 5*11+2, t=55+2, t=57, then u = 2*11+9, u=22+9, u=31, and lastly v=8*11+4, v= 88+4, and v=92

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Can someone help me with please??

OverLord2011 [107]

Answer:

The angle is 35 degrees

Step-by-step explanation:

Since this is an isosceles triangle, we know that the two remaining angles must be the same. Set those angles equal to x. Now, we can solve for x by adding those two angles to the third angle and setting equal to 180.

x + x + 110 = 180

2x + 110 = 180

2x = 70

x = 35

6 0

3 years ago

Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)

Crazy boy [7]

Answer:

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Step-by-step explanation:

To find : Convert $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}$ into $\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Solution :

We convert units one by one,

$1\text{ m}^2=10.7639\text{ ft}^2$

$1\text{ sec}=\frac{1}{3600}\text{ hour}$

$1\text{ cal}=0.003968\text{ BTU}$

Converting temperature unit,

$^\circ C\times \frac{9}{5}+32=^\circ F$

$1^\circ C\times \frac{9}{5}+32=33.8^\circ F$

So, $1^\circ C=33.8^\circ F$

Substitute all the values in the unit conversion,

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$