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professor190 [17]
3 years ago
11

Does 6.3=6.33 plz help

Mathematics
1 answer:
KATRIN_1 [288]3 years ago
3 0

no

it does not

6.3 is 6.30

6.33 is not equal to 6.30

so the answer is No

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A small town has 2000 inhabitants. At 8 AM, 160 people have heard a rumor. By noon half the town has heard it. At what time will
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Answer:

3:36 PM

Step-by-step explanation:

Let fraction (y) of the people that heard the rumor , the differential equation that is satisfied by the by y is,

                            \frac{dy}{dt} = ky(1-y)

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                          y(t) = \frac{y_{o}}{[y_{o} + (1 + y_{o})e^{-kt}]}

The total number of inhabitants of the town = 2000

The number of people that  heard the rumor = 160

At 8 AM, let t = 0,

               y(0) = \frac{160}{2000}

                       = 0.08

By noon, half of the town as heard the rumor.

Then,    

                y(4) = \frac{1}{2}

Therefore,

              \frac{1}{2} = \frac{0.08}{[0.08 + (1 - 0.08)e^{-4k}]}

              \frac{0.08}{[0.08 + 0.92e^{-4k}]} = \frac{1}{2}

              0.08 + 0.92e^{-4k} = 0.16  

              0.92e^{-4k} = 0.16 - 0.08

              0.92e^{-4k} = 0.08

              e^{-4k} = \frac {0.08}{0.92}

              k = - \frac{1}{4} In(\frac {0.08}{0.92})

              k ≈ 0.06106

Calculating time, t when y(t) = 90%

        ⇒ y(t) = 0.9

              \frac{0.08}{[0.08 + 0.92e^{-0.06106t}]} =0.9

              0.08 + 0.92e^{-0.06106t} = \frac {0.9}{0.08}

              0.08 + 0.92e^{-0.06106t} = 0.089

              0.92e^{-0.06106t} = 0.089 - 0.08

              0.92e^{-0.06106t} = 0.0089

              t = - \frac{1}{0.06106}In (\frac{0.0089}{0.92})

              t = 7.59 hours

              ⇒ 7 hours 36 minutes

From 8 A.M. plus 7 hours 36 minutes = 3:36 PM

At 3:36 PM will 90% of the population have heard the rumor

             

             

             

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Me podrían ayudar a contestar estas preguntas, por favorspeak spanish
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Con ello, podemos decir que:

a. Los lados RS y UT son paralelos.

b. Los lados RU y ST son paralelos.

c. El angulo en U es igual al angulo en S pues son opuestos

d. Los angulos en S y T son adjacentes . Esto quiere decir que, su suma es igual a 180 grados.

e. El angulo en R es igual al angulo en T pues son opuestos.

f. De forma similar al caso d, los angulos U y R son adjacentes, su suma es 180 grados.

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