Question

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Answer 1

Answer:

$y^2+49=(y-7i)(y+7i)$

Step-by-step explanation:

Given : Expression $y^2+49$

To find : Factor the expression over the complex numbers ?

Solution :

To factor the expression we equate it to zero and find the values of y,

$y^2+49=0$

Subtract 49 both side,

$y^2=-49$

Taking root both side,

$y=\sqrt{-49}$

We know, $\sqrt{-1}=i,\ \sqrt{49}=7$

$y=\pm 7i$

The factors are $(y-7i)(y+7i)$

Therefore, $y^2+49=(y-7i)(y+7i)$

Answer 2

$Use\\\\a^2-b^2=(a-b)(a+b)\\\\i=\sqrt{-1}\to i^2=-1\\\\y^2+49=y^2+7^2=y^2-(-1)(7^2)=y^2-(7i)^2\\\\=(y-7i)(y+7i)$