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2 years ago

Anybody know the answer?

Mathematics

1 answer:

Dmitry_Shevchenko [17]2 years ago

8 0

Answer:

<h2>Option B </h2>

Step-by-step explanation:

As,

It has shown that line c cuts line b by making 90° so those lines are called perpendicular bisectors .

Hence,

Option B is the correct symbol shown for perpendicular bisector of line c to line b.

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Can someone please help me I’ve tried so many ways and still can’t get the answer.

mr Goodwill [35]

Answer:

15.22

Step-by-step explanation:

The equation of the circumference of a circle is 2(pi)r

This is actually because 2pi is angle of the arc that makes up the full circle (radians of course)

so a simple formula is:

arc length in radians X radius

radius = 4 cm

the area that the question wants is the oposite

of the 142 degree section so 360 - 142 = 218

218 degrees * (pi/180) = 3.80482 rad

3.80482 * 4 = 15.21928 cm

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2 years ago

Danna's age is 6 years less than 8 times Tessa's age. If Tessa's age is x years, which expression best shows Danna's age?

Marat540 [252]

6 - 8x is the correct answer

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3 years ago

Read 2 more answers

4-x/5 =x-4/6 please help me with this question

marshall27 [118]

Answer:

answer is 0 meaning there is no solution

Step-by-step explanation:

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2 years ago

What is a factor of 21x² + 13x - 20

Tems11 [23]

Answer:

(7x-5)(3x+4)

Step-by-step explanation:

4 0

2 years ago

How are percent transmittance and absorbance related algebraically?

statuscvo [17]

Answer:

So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.

Absorbance is the inverse of transmittance so,

A = 1/T

Beer's law (sometimes called the Beer-Lambert law) states that the absorbance is proportional to the path length, b, through the sample and the concentration of the absorbing species, c:

A ∝ b · c

As Transmittance, $T =\dfrac{P}{P_0}$

% Transmittance, $\%T=100\times T$

Absorbance,

$A=\log_{10} \dfrac{P_0}{P}\\\\A =\log_{10}\times \dfrac{1}{T}\\\\A=\dfrac{\log_{10} 100}{\%T}\\\\A=(2 - log_{10})\times \%T$

Hence, $A=\log_{10}\times \dfrac{1}{T}$ is the algebraic relation between absorbance and transmittance.

8 0

2 years ago