We are given the equation <span>an = (n^2/ sqrt(n^3+4n)) and asked to determine if the function is divergent or convergent. In this case, we find the limit of the function as n approaches infinity.
an = </span><span> (n^2/ sqrt(n^3+4n))
lim (n to infinity ) = infinity / infinty: ;indeterminate
Using L'hopitals rule, we derive
</span><span>lim (n to infinity ) = 2 n / 0.5* ( </span><span>n^3+4n) ^-0.5 * (3 n2 +4) : infinity / infinity
again, we derive
</span>lim (n to infinity ) = 2 (0.25) (( n^3+4n) ^-0.5))*(3 n2 +4) / 0.5* ( 6n + 4) :infinity / infinity
<span>
again,
</span>lim (n to infinity ) = 2 (0.25) (6n + 4) / 0.5* ( 6)* 0.5 <span>(( n^3+4n) ^-0.5))</span>
this goes on and the function is divergent
Answer:
18/2 is 9
Step-by-step explanation:
2*9 is 18
<span>0x14BD. hope it helped
</span>
Hi there! :)
Answer:

Given line with an equation of y = 4x + 3
Parallel lines contain equivalent slopes, so a parallel line to the given equation would contain a slope of m = 4.
Plug in the coordinates of the point given, along with the slope into the equation y = mx + b where:
m = slope
y = y-coordinate of point
x = x-coordinate of point
Solve for the 'b' value, or y-intercept:
y = mx + b
6 = 4(2) + b
6 = 8 + b
b = -2
Rewrite the equation as slope-intercept form:
y = 4x - 2