Pls help me out!!!!!!!!
1 answer:
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As a matter of simplification, same/same = 1.
now, "same" could be anything whatsoever, you name it, a whole polynomial, a whole anything whatsoever.
![\bf \cfrac{\sqrt{2}}{\sqrt{2}}=\cfrac{\sqrt{3}}{\sqrt{3}}=\cfrac{100000000}{100000000}=\cfrac{eggs}{eggs}=\cfrac{miles}{miles}=\cfrac{\frac{\quad \sqrt{3}}{\sqrt[5]{17}}\quad }{\frac{\sqrt{3}}{\sqrt[5]{17}}}=\cfrac{whatever}{whatever}=1](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B%5Csqrt%7B2%7D%7D%7B%5Csqrt%7B2%7D%7D%3D%5Ccfrac%7B%5Csqrt%7B3%7D%7D%7B%5Csqrt%7B3%7D%7D%3D%5Ccfrac%7B100000000%7D%7B100000000%7D%3D%5Ccfrac%7Beggs%7D%7Beggs%7D%3D%5Ccfrac%7Bmiles%7D%7Bmiles%7D%3D%5Ccfrac%7B%5Cfrac%7B%5Cquad%20%5Csqrt%7B3%7D%7D%7B%5Csqrt%5B5%5D%7B17%7D%7D%5Cquad%20%7D%7B%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B%5Csqrt%5B5%5D%7B17%7D%7D%7D%3D%5Ccfrac%7Bwhatever%7D%7Bwhatever%7D%3D1)
now, that said, let us use 1 in this case then ... hmmmm we simply need a "y" in the denominator, so we simply multiply the denominator AND numerator by "y", y/y = 1 btw.
now, "same" could be anything whatsoever, you name it, a whole polynomial, a whole anything whatsoever.
now, that said, let us use 1 in this case then ... hmmmm we simply need a "y" in the denominator, so we simply multiply the denominator AND numerator by "y", y/y = 1 btw.
Answer:
464 grams.
Step-by-step explanation:
Amount of substance:
The amount of substance after t years is given by an equation in the following format:
In which A(0) is the initial amount and r is the decay rate, as a decimal.
Co-60 has a half life of 5.3 years.
This means that:
We use this to find r. So
So
If a pellet that has been in storage for 26.5 years contains 14.5g of Co-60, how much of this radioisotope was present when the pellet was put in storage?
We have that , and use this to find A(0). So
[tex]A(0) = 464[tex]
464 grams.