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3 years ago

7

Alexis is knitting a blanket 2 meters long. Every 2 decimeters, she changes the color of the yarn to make stripes. How many stri

pes will the blanket have?

1 answer:

Aliun [14]3 years ago

7 0

Answer:

There are 10 stripes in the blanket.

Step-by-step explanation:

We are given the following in the question:

Length of blanket = 2 meters

1 meter = 10 decimeter

Length of blanket in decimeter =

$2\times 10 = 20\text{ decimeters}$

Change of color = Every 2 decimeters.

Number of stripe =

$=\dfrac{\text{Length of blanket}}{\text{Length of change of color of stripe}}\\\\=\dfrac{20}{2} = 10$

Thus, there are 10 stripes in the blanket.

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Which set of side lengths is a pythagorean triple

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Several examples of side lengths that are Pythagorean triples are the following with the corresponding side lengths A, B, C:

(5, 12, 13), (7, 24, 25), (3, 4, 5)

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3 years ago

Consider the graph of the line y = x – 4 and the point (−4, 2).

Hitman42 [59]

Answer:

a. The slope of a line parallel to the given line is 1

b. A point on the line parallel to the given line, passing through (−4, 2), is (1,7)

c. The slope of the line perpendicular to the given line is -1

d. A point on the line perpendicular to the given line, passing through (−4, 2), is (3,-5)

Step-by-step explanation:

The equation of the line in Slope-intercept form is:

$y=mx+b$

Where m is the slope and b is the y-intercept.

a. For the line $y = x - 4$

You can identify that:

$m=1$

By definition, two lines are parallel if they have the same slope. Then, the slope of a line parallel to the given line is:

$m=1$

b. The equation of the line in Point-slope form is:

$y -y_1 = m(x - x_1)$

Where m is the slope and ( $x_1,y_1$ ) is a point of the line.

Given the point (-4,2), substitute this point and the slope of the line into the equation:

$y -2 = (x +4)$

Give a value to "x", substitute it into this equation and solve for "y":

For $x=1$ :

$y -2 = (1 +4)$

$y= 5+2$

$y= 7$

Then, you get the point (1,7)

c. The slopes of perpendicular lines are negative reciprocals, then the slope of a line perpendicular to the given line is:

$m=-\frac{1}{1}\\\\m=-1$

d. Given the point (-4,2), substitute this point and the slope of the line into the equation:

$y -2 = -1(x +4)$

$y -2 = -(x +4)$

Give a value to "x", substitute it into this equation and solve for "y":

For $x=3$ :

$y -2 = -(3 +4)$

$y= -7+2$

$y= -5$

Then, you get the point (3,-5)

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3 years ago

Car leases generally allow only a certain number of miles to be driven. Myung’s lease included a charge of 25 cents per mile for

KengaRu [80]

Answer:

197

Step-by-step explanation:

Divide 1640 by 25

1640/25=65

Then multiply 65 and 3

65x3=197

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3 years ago

Read 2 more answers

A major cab company in Chicago has computed its mean fare from O'Hare Airport to the Drake Hotel to be $28.75 , with a standard

bulgar [2K]

Answer:

Following are the solution to the given choices:

Step-by-step explanation:

Using chebyshev's theorem :

$\to P(|(x-\mu)|\leq k \sigma)\geq 1- \frac{1}{k^2}\\\\here \\ \to \mu=28.75\\\\ \to \sigma=4.44$

In point a)

$\to |(x-\mu)|= |20.17-28.75|=8.58 and \sigma=4.44 \\\\so, \\k= \frac{ |(x-\mu)| }{\sigma}$

$= \frac{8.58}{4.44} \\\\ =1.9 \\\\ =2$

$value= (1- \frac{1}{k^2}) \times 100 \% =75\%$

In point b)

$\to (1- \frac{1}{k^2}) \times 100 \% =84\% \\\\\to (1- \frac{1}{k^2})=0.84 \\\\\to \frac{1}{k^2} =0.16 \\\\\to \frac{1}{k}=0.4\\\\ \to k=2.5 \\\\\to |(x-\mu)| \leq k \sigma \\\\= |(x-\mu)|\leq 2.5 \times 4.44 \\\\ = |(x-\mu)|\leq 1.11 \\\\ = (28.75\pm 11.1) \\\\\to \text{fares lies between}(17.65,39.85)$

In point c)

$\to 99.7 \% \\ lie \ between=28.75 \pm z(.03)\times \sigma \\\\ =28.75\pm 2.97 \times 4.44\\\\=(28.75\pm 13.1)\\\\=(15.65,41.85)\\$

In point d)

using standard normal variate

$x=20.17\\\\ z=-2 \\\\x=37.13\\\\ z=2\\\\\to P(20.17$

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Find the value of y of the figure below.

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I hope this helps you

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