Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE=2x, BE=y+10, CE=x+2 and DE=4y−8. Find the length of AC.
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Answer:
The probability that the sum of the dice is less than 400 is 0.3050.
Step-by-step explanation:
Let <em>X</em> = outcomes of a single roll of a dice.
The possible outcomes of <em>X</em> are
S = {1, 2, 3, 4, 5, 6}
The probability of the random variable <em>X</em> is:
Compute the mean and variance of the random variable <em>X</em> as follows:
The dice was rolled <em>n</em> = 117 times.
The sum of the values of <em>X</em> in these 117 rolls follows a Normal distribution with mean 3.5 and variance 2.917.
Compute the probability that the sum of the dice is less than 400 as follows:
*Use the <em>z</em>-table for the probability.
Thus, the probability that the sum of the dice is less than 400 is 0.3050.
