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liberstina [14]
3 years ago
12

Given parallelogram ABCD, diagonals AC and BD intersect at point E. AE=2x, BE=y+10, CE=x+2 and DE=4y−8. Find the length of AC.

Mathematics
1 answer:
WARRIOR [948]3 years ago
6 0

Answer: 8 units

Step-by-step explanation:

The diagonals of a parallelogram bisect each other, so you can set AE and CE equal to each other, as well as BE and ED

2x=x+2

x=2

AC=2x+x+2

AC=3x+2

SUbstitute x

AC=3(2)+2

AC=6+2

AC=8

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Step-by-step explanation:

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Kruka [31]

Answer:

Firstly, from the diagram we are given that the length of XB is congruent to BZ, and YC is congruent to CZ. Based on this information, we know that B is the midpoint of XZ, and C is the midpoint of YZ. This means that BC connects the midpoints of segments XZ and YZ. Now that we know this, we can use the Triangle Midsegment Theorem to calculate the length of BC. This theorem states that if a segment connects the midpoints of two sides of a triangle, then the segment is equal to one-half the length of the third side. In this scenario, the third side would be XY, which has a length of 12 units. Therefore, the length of BC = 1/2(XY), and we can substitute the value of XY and solve this equation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Option 1:

Using the following rule:

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Option 2:

Using the following rule:

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Since our expression is the same as multiplying 2³ with itself, we can write it as a multiplication.

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4 years ago
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