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Alchen [17]
3 years ago
9

the figure below to answer the questions that follow 6cm LO 3.3.1 Calculate the angle, 60, in radians. (2) 3.3.2 Calculate the a

rea of the minor sector (the "slice that has been cut out). (3) 3.3.3 Calculate the area of the major sector (4) 3.3.4 Calculate the arc length of the minor sector (3) 3.3.5 Calculate the arc length of the major sector. (3) [30]​
Mathematics
1 answer:
Mrrafil [7]3 years ago
3 0

Answer:

it's very hard

im sorry dunno

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Makovka662 [10]

Answer: 3/5

Step-by-step explanation

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3 years ago
(log, 4 +log, 16) - log, 2
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Answer:

1.5051

Step-by-step explanation:

3 0
3 years ago
The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes was 7 to 5 . If there were
Nitella [24]

Answer: 6456

Step-by-step explanation:

Ratio of yes to no= 7:5

Number if yes= 3766

Since total number of yes is 3766. To find the total number of votes, 3766 / (7/7+5)

= 3766/ (7/12)

= 3766 × 12/7

= 45192/7

= 6456

There were 6456 total votes

5 0
3 years ago
A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic
goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event <em>E</em>_{i}, of the sample space <em>S,</em> given that another event <em>A</em> has already occurred is:

P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}

The law of total probability states that, if events <em>E</em>₁, <em>E</em>₂, <em>E</em>₃... are parts of a sample space then for any event <em>A</em>,

P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}

Denote the events as follows:

<em>X</em> = fetus have a chromosome abnormality.

<em>Y</em> = the test is positive

The information provided is:

P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85

Using the above the probabilities compute the remaining values as follows:

P(X^{c})=1-P(X)=1-0.04=0.96

P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10

P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})

          =(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}

             =\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}

             =0.20

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0
3 years ago
ILL GIVE BRAINLIST
zubka84 [21]

Answer:

13

Step-by-step explanation:

8 0
3 years ago
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