Let
ba--------> area of bases (<span>the two bases included</span>)
p---------> perimeter of the base
h--------> height of the prism
la-------> lateral area
we know that
[surface area]=2*[area of one base]+[perimeter of the base]*height
so
2*[area of one base]=ba
[surface area]=[ba]+[p]*h
and
the formula of lateral area is
[la]=[perimeter of the base]*height
[la]=[p]*h
therefore
[surface area]=[ba]+[la]
the answer is
[surface area]=[ba]+[p]*h
[surface area]=[ba]+[la]
Answer:
46°
Step-by-step explanation:
The alternate segment theorem states that for a circle, the angle between a chord and a tangent through the endpoint of one of the chord is equal to the angle in the alternate segment.
Therefore from the diagram attached, chord TU and the tangent UV form an angle (arc TBU). The alternate segment to arc TBU is ∠ TUV .
Therefore arc TBU = ∠ TUV. But arc TBU = 46°. Therefore:
∠ TUV = 46°
Answer:
2
Step-by-step explanation:
Answer: 320
Step-by-step explanation:
