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lana66690 [7]
4 years ago
5

A corporation reported profit of approximately $1500 million with approximately $24,300 million in revenues. Compare the profit

to revenue by writing as a fraction in the lowest terms
Mathematics
1 answer:
Alecsey [184]4 years ago
7 0

Answer:

\frac{5}{81}

Step-by-step explanation:

Given:

Profit = $1500 million

Revenue = $24,300 million

Profit to Revenue = \frac{1500 million}{24,300 million}       [Since they both have same unit ($), this sign can be omitted]

<em>Now let's reduce the ratio above to its lowest terms...</em>

\frac{1500 million}{24,300 million}

[First, the millions at the numerator and denominator cancel out]

\frac{1500}{24,300}  

[Next, the two zeros at the numerator and denominator cancel out]

\frac{15}{243}

[Next, divide both the numerator and denominator by 3]

\frac{5}{81}

Since no further division can be done, then the profit to revenue is in its lowest terms as \frac{5}{81}

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7 0
3 years ago
A bengal tigers tail is around 30% of its total length. The total length of one bengal tiger's tail is 96 cm. Around how long is
Paraphin [41]

Answer:

The length of the tiger is 320 cm.

Step-by-step explanation:

Let the height of a bengal tiger be x.

It is given that the length of tiger tail is around 30% of its total length.

The length of tiger's tail is \frac{30}{100}x.

The total length of a bengal tiger's tail is 96 cm.

\frac{30}{100}x=96

30x=9600

x=\frac{9600}{30}

x=320

Therefore the length of the tiger is 320 cm.

5 0
4 years ago
A sample of a radioactive isotope had an initial mass of 360 mg in the year 1998 and
RUDIKE [14]

Answer:

193 mg

Step-by-step explanation:

Exponential decay formula:

  • A_t = A_0e^r^t
  • where Aₜ = mass at time t, A₀ = mass at time 0,  r = decay constant (rate), t = time  

Our known variables are:

  • 1998 to the year 2004 is a total of t = 6 years.
  • The sample of radioactive isotope has an initial mass of A₀ = 360 mg at time 0 and a mass of Aₜ = 270 mg at time t.

Let's solve for the decay constant of this sample.

  • 270=360e^-^r^(^6^)
  • 270=360e^-^6^r
  • \frac{3}{4} =e^-^6^r
  • \text{ln} (\frac{3}{4} )= \text{ln}(e^-^6^r)
  • \text{ln} (\frac{3}{4} )=-6r
  • r=-\frac{\text{ln}\frac{3}{4} }{6}
  • r=0.04794701

Using our new variables, we can now solve for Aₜ at t = 7 years, since we go from 2004 to 2011.

Our new initial mass is A₀ = 270 mg. We solved for the decay constant, r = 0.04794701.

  • A_t=270e^-^(^0^.^0^4^7^9^4^8^0^1^)^(^7^)
  • A_t=270e^-^0^.^3^3^5^6^2^9^0^7
  • A_t=193.01982213

The expected mass of the sample in the year 2011 would be 193 mg.

3 0
3 years ago
A rectangular field is eight times as long as it is wide. If the perimeter of the field is 900 feet, what are the dimensions of
Bas_tet [7]

Answer:

400 feet long

50 feet wide

Step-by-step explanation:

Length = l

Width = w

2l + 2w = 900

l = 8w

Plug the l from the bottom equation into the top equation

2 x 8w+ 2w = 900

16w = 900

Divide both sides by 16

16w/16 = 900/16

w = 50

The width is 50 feet

Now plug the new w into one of the original equations; we'll use the bottom one

l = 8(50)

l = 400

3 0
3 years ago
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