6.47x10^-4
Step-by-step explanation:
Answer:
x=3, y=1
Step-by-step explanation:
2x+y =7
3x-4y =5
Multiply the first equation by 4 so we can eliminate y
4(2x+y =7)
8x +4y =28
Add this to the second equation
8x +4y =28
3x-4y =5
----------------
11x = 33
Divide by 11
11x/11=33/11
x=3
Now we still need to find y
2x+y=7
2(3)+y =7
6+y=7
Subtract 6 from each side
6-6+y=7-6
y= 1
Answer:
no
Step-by-step explanation:
no
Step 1: Find the slope:
This gives you 
, but we need to find b.
To find b, substitute in one (x,y) pair and it doesn't matter which one. I'll go with (4,-2):
![\begin{aligned}-2&=-\dfrac{3}{2}(4)+b\\[0.5em]-2&=-6+b\\[0.5em]4&=b\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D-2%26%3D-%5Cdfrac%7B3%7D%7B2%7D%284%29%2Bb%5C%5C%5B0.5em%5D-2%26%3D-6%2Bb%5C%5C%5B0.5em%5D4%26%3Db%5Cend%7Baligned%7D)
Now take that b-value and plug in into the slope-intercept form:
It's always a good idea to toss in the other x-value from the other point, to make sure it checks out.
Given: <span>y = x^2 + 6x - 5. Then a = 1, b = 6 and c = -5.
The x-coord. of the vertex is given by x = -b / (2a), which here is x = -6 / (2*1) = -3.
Use the given formula </span><span>y = x^2 + 6x - 5 to find the value of y when x = -3:
y = (-3)^2 + 6(-3) - 5 = 9 - 18 - 5 = -14
Then the vertex is (-3, -14).</span>
