A1=24
<span>n=500(seq #) </span>
<span>d=how much u add each time=6 </span>
<span>a(n)=24+(500-1)(6)=3018</span>
Let c=cost of chicken and d=cost of duck; 50c+30d=550 and 44c+36d=532.
So 5c+3d=55, 11c+9d=133.
Therefore 15c+9d=165, subtracting 11c+9d=133 we get: 4c=32 so c=8.
5c+3d=40+3d=55, so 3d=15 and d=5.
Cost of chicken is $8 and cost of duck is $5.
Answer:
Range of the given function = -4
Step-by-step explanation:
Range is the set of output values.
In a graph, the set of x-values of the function is know as domain and the set of y-values of the function is known as range.
In the graph red line represents the function.
From the given graph it is clear that the function is defined from x=-1 to x=4.
For each value of x the y-value is -4.
Hence, the range of the function is -4.
Answer:
2
Step-by-step explanation:
