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Dovator [93]
3 years ago
10

2. An expression is shown below.

Mathematics
1 answer:
velikii [3]3 years ago
5 0
The answer is B12 hope this helped
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If someone treat at geometry has anyntime could you come answer my question
ki77a [65]
I am pretty good at any math and I love a good challenge. What is your question because I'd be glad to help!!!
4 0
4 years ago
There are a total of 64 students in a drama club and a yearbook club. The drama club has 10 more students than the yearbook club
g100num [7]
Given:
64 total students
x = drama club students
y = yearbook club students

x = y + 10
y = 64 - x

y = 64 - x
y = 64 - (y + 10)
y = 64 - y - 10
y + y = 64 - 10
2y = 54
2y/2 = 54/2
y = 27

x = y + 10
x = 27 + 10
x = 37 

To check:

x + y = 64
37 + 27 = 64
64 = 64

8 0
4 years ago
3/7+-5/11+-5/14+3/11​
Pachacha [2.7K]

Answer:

Hey!

Your answer is 1\frac{5}{8}!

Step-by-step explanation:

Also can be written as 41/8!

HOPE THIS HELPED!

3 0
3 years ago
Read 2 more answers
Why do you multiply 12 by 3 to find the total number cubes in the bottom 3 layers
BaLLatris [955]

because there are 12 in one layer and there are 3 layers

4 0
3 years ago
Write an equation of the perpendicular bisector of the segment with endpoints G 9,8       and H 3,2      .
Norma-Jean [14]

Answer:

y = -x + 11

Step-by-step explanation:

The equation of a straight line is is given by:

y = mx + b; where m is the slope and b is the y intercept

The equation of the line joining G(9, 8) and H(3, 2) is given as:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\y-8=\frac{2-8}{3-9}(x-9)\\\\y-8=x-9\\\\y=x-1

The perpendicular bisector of the line joining G(9, 8) and H(3, 2) is perpendicular to the line joining G(9, 8) and H(3, 2) and passes through the midpoint of line joining G(9, 8) and H(3, 2).

Let (x, y) be the midpoint of the line joining G(9, 8) and H(3, 2). Hence:

x = (9 + 3)/2 = 6

y = (8 + 2)/2 = 5

The midpoint = (6, 5)

Two lines are perpendicular if the product of their slopes is -1.

The line joining G(9, 8) and H(3, 2) has a slope of 1, hence, the slope of the perpendicular bisector would be -1.

This means that the perpendicular bisector has a slope of -1 and passes through (6, 5). Using:

y-y_1=m(x-x_1)\\\\y-5=-1(x-6)\\\\y-5=-x+6\\\\y=-x+11

The equation of the perpendicular bisector is y = -x + 11

8 0
3 years ago
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