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schepotkina [342]
3 years ago
5

In ATUV, TV is extended through point V to point W,

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
6 0

Answer:

m∠UVW = 53°

Step-by-step explanation:

From the picture attached,

m(∠VTU) = (x - 2)°

m(∠TUV) = (2x + 11)°

m(∠UVW) = (6x - 15)°

Since, ∠UVW is the exterior angle of the ΔTUV,

By the triangle sum theorem,

m∠VTU + m(∠TUV) + m(∠UVW) = 180°

(x - 2)° + (2x + 11)° + (6x - 15)° = 180°

9x - 6 = 180

9x = 186

x = \frac{186}{9}

x = \frac{62}{3}

By the property of exterior angle of a triangle,

m(∠UVW) = m(∠VTU) + m(TUV)

                = (x - 2) + (2x + 11)

                = 3x - 9

Now by substituting the value of x,

(3x - 9)° = 3(\frac{62}{3})-9

           = 62 - 9

           = 53°

Therefore, m∠UVW = 53°

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a) i) No

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Step-by-step explanation:

Part a) Without replacement:

i) Are these events independent?

No, because the both events are dependent. because a card taken out of the deck is not replaced back before taking out the other card so the chances of event occur change.

ii) Determine the probability of drawing a diamond and then a spade without replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

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Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after taking diamond = 52 -1 =51

Spades = 13

Probability of drawing a spade  = 13/51

Probability of drawing a diamond and then spade = 13/52 * 13/51

= 169/2652

=0.0637

So, Probability of drawing a diamond and then spade without replacement  is 0.0637

Part b) With replacements

i) Are these events independent?

Input Yes or No:

Yes, these events are independent because a card taken out of the deck is replaced back before taking out the other card so the chances of event occur doesn't change.

ii) Determine the probability of drawing a diamond and then a spade with replacement.

Probability of drawing a diamond and then spade = (Probability of drawing a diamond) * (Probability of drawing a spade)

Probability of drawing a diamond :

Total cards in deck = 52

Diamonds = 13

Probability of drawing a diamond  = 13/52

Probability of drawing a spade:

Total cards in deck after replacing diamond = 52

Spades = 13

Probability of drawing a spade  = 13/52

Probability of drawing a diamond and then spade = 13/52 * 13/52

= 169/2704

=0.0625

So, Probability of drawing a diamond and then spade with replacement is 0.0625

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