This question is incomplete, the complete question is;
In an interval whose length is z seconds, a body moves (32z + 2z²) ft.
What is the average speed v of the body in this interval?
Answer: the average speed v of the body in this interval is 32 + 2z ft/s
Step-by-step explanation:
Given that;
Length of travel = z seconds
also the body moves (32z + 2z²) ft
i.e
distance travelled = (32z + 2z²) ft
average speed v of the body in this interval = ?
Now to get the Average Speed
we simply say;
Average Speed V = (32z + 2z²) / z
Average Speed V = 32 + 2z ft/s
Therefore the average speed v of the body in this interval is 32 + 2z ft/s
