Answer:
P_max = 9.032 KN
Step-by-step explanation:
Given:
- Bar width and each side of bracket w = 70 mm
- Bar thickness and each side of bracket t = 20 mm
- Pin diameter d = 10 mm
- Average allowable bearing stress of (Bar and Bracket) T = 120 MPa
- Average allowable shear stress of pin S = 115 MPa
Find:
The maximum force P that the structure can support.
Solution:
- Bearing Stress in bar:
T = P / A
P = T*A
P = (120) * (0.07*0.02)
P = 168 KN
- Shear stress in pin:
S = P / A
P = S*A
P = (115)*pi*(0.01)^2 / 4
P = 9.032 KN
- Bearing Stress in each bracket:
T = P / 2*A
P = T*A*2
P = 2*(120) * (0.07*0.02)
P = 336 KN
- The maximum force P that this structure can support:
P_max = min (168 , 9.032 , 336)
P_max = 9.032 KN
Answer:
0
Step-by-step explanation:
find mean : 2+3+4+7 divided by 4 equals 4
subtaract mean from valuses: 2-4= -2 , 3-4= -1 , 4-4= 0 , 7-4= 3 ,
find mean with new numbers: -2+-1+3+0 divided by 4 equals 0 (everything cancels out)
Answer:
1/4
Step-by-step explanation:
coins have 2 sides, tails and heads, so for it to land on tails is a 1/2 chance. Dice have 6 sides and 1,3,5 are all odd so its a 3/6 chance. Simplify 3/6 to 1/2 and multiply by 1/2 to get 1/4. im not sure, its my guess.