Question

Solve for x.this is for the k12 test.​

Answer 1

Answer:

option D

Step-by-step explanation:

$\sqrt{10x+50}=x+5\\\\(\sqrt{10x+50})^2=(x+5)^2\\\\10x+50=x^2+10x+25\\\\0=x^2+10x-10x+25-50\\\\0=x^2-25\\\\0=(x-5)(x+5)\\\\x=5\\\\x=-5$

now trying for the original equation

$\sqrt{10(5)+50}=5+5\\\\\sqrt{50+50}=10\\\\\sqrt{100}=10\\\\10=10$

and

$\sqrt{10(-5)+50}=-5+5\\\\\sqrt{-50+50}=0\\\\\sqrt{0}=0\\\\0=0$

so it's option D

Answer 2

Answer:

d

Step-by-step explanation: