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4 years ago

A) (90 - 24,^3 = Helppppppp

Mathematics

1 answer:

elena55 [62]4 years ago

6 0

Answer:

-13734

Step-by-step explanation:

We're going to use pemdas for this equation.

Since there are no parenthesis we move on to exponents, which we do have, so we would cube 24, which gets us 13,824.

Next we subtract 90 from 13,824 which gives us our answer of -13,734

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The graph shows the total mass loss of the Greenland ice sheet since 2007. Write a conjecture using the graph.

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The conjecture or hypothesis given based on the attached graph is that there has been a general increase in the total loss of the Greenland Ice Sheet since 2007. However, since 2013, the rate at which the total loss increased began to decline.

<h3>What is a conjecture in math?</h3>

In mathematics, a hypothesis or a conjecture is a speculative conclusion or assertion that is stated without evidence.

<h3>How do you write a Conjecture ?</h3>

You must discover a trend or make some type of remark. For example, you may have observed that the list is increasing by twos.

You draw a conclusion based on the pattern you saw, just as you did when you determined that 18 would be the following number.

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2 years ago

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3 years ago

Only number 5, check image above for question. Please help. Whichever answer helps best I’ll mark as “Brainliest Answer”.

GarryVolchara [31]

I think it is 20%. I'm, not 100% percent sure.

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4 years ago

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Answer:

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3 years ago

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One of the legs of a right triangle is twice as long as the other, and the perimeter of the triangle is 28. Find the length of t

Nutka1998 [239]

1) If we let the lengths of the legs be x and 2x, then by the Pythagorean theorem,

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This means that the length of the hypotenuse is:

$\sqrt{5}(21-7\sqrt{5})=\boxed{21\sqrt{5}-35}$

2) (Diagram attached) We know that

$\cos 51^{\circ}=\frac{x}{58}\\x=58 \cos 51^{\circ} \approx \boxed{36.5}$ (in cm)

3) From the Pythagorean identity,

$\sin^{2}\left (\arccos \frac{5}{13} \right)+\cos^{2} \left (\arccos \frac{5}{13} \right)=1\\\left(\frac{5}{13} \right)^{2}+\sin^{2} \left (\arccos \frac{5}{13} \right)=1\\\frac{25}{169}+\sin^{2} \left (\arccos \frac{5}{13} \right)=1\\\sin^{2} \left (\arccos \frac{5}{13} \right)=\frac{144}{169}\\\sin \left (\arccos \frac{5}{13} \right)=\boxed{\frac{12}{13}}$

4) $\frac{\pi}{6}$

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2 years ago