B, the first differences are not the same , that proves it is not linear. The second set of differences are the same this shows it is a quadratic function.
Answer:
<em>Hence the daughter's present age is 15 years</em>
<em>The fathers present age is 35 years</em>
<em></em>
Step-by-step explanation:
Let the present age of daughter be x
Let the present age of father be y
5 years ago;
Daughter's age = x - 5
Fathers age = y - 5
If the present age of father is thrice as old as the age of daughter 5 years ago, then;
y - 5 = 3(x-5)
y - 5 = 3x-15
y = 3x - 10 .... 1
In 5 years time;
Daughters age = x + 5
Fathers age = y + 5
If the age of father will be twice the age of his daughter in 5 years time then;
y+5 = 2(x+5)
y+5 = 2x + 10
y = 2x + 5 .....2
Equate 1 and 2;
3x - 10 = 2x + 5
3x - 2x = 5 + 10
x = 15
Since y = 2x + 5
y = 2(15) + 5
y = 35
<em>Hence the daughter's present age is 15 years</em>
<em>The fathers present age is 35 years</em>
<em></em>
W = 3A - 6
W = 33
33 = 3A - 6
33 + 6 = 3A
39 = 3A
39/3 = A
13 = A.....he is 13
Answer:
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
By:
I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34