Step-by-step explanation:
<h2>
<em>y = ± 5⁄2 x</em></h2><h2>
<em>y = ± 5⁄2 xThe equation is the left half of the hyperbola. The domain is ( – ∞, – 1⁄5 ]. The range is ( – ∞, ∞ ). The vertical line test indicates that this is not the graph of a function.</em></h2>
<em>x</em>/<em>r</em> + <em>x</em>/<em>w</em> + <em>x</em>/<em>t</em> = 1
<em>x</em> (1/<em>r</em> + 1/<em>w</em> + 1/<em>t</em>) = 1
<em>x</em> = 1 / (1/<em>r</em> + 1/<em>w</em> + 1/<em>t</em>)
To make the solution a bit cleaner, multiply through the numerator and denominator by the LCM of each fraction's denominator, <em>rwt</em> :
<em>x</em> = 1 / (1/<em>r</em> + 1/<em>w</em> + 1/<em>t</em>) • <em>rwt</em> / <em>rwt</em>
<em>x</em> = <em>rwt</em> / (<em>rwt</em>/<em>r</em> + <em>rwt</em>/<em>w</em> + <em>rwt</em>/<em>t</em>)
<em>x</em> = <em>rwt</em> / (<em>wt</em> + <em>rt</em> + <em>rw</em>)
In this question, we have a graph given. And using that graph we have to find the value of f(1) .
f(1) means the y value when x=1 .
So we need to check the value of y at x=1 .
And if we follow the graph, we will see that at x=1, y=2.5 . So the value of f(1)=2.5 and that's the required answer .
A.
A = 400 (1 + (0.02)/4)^4t where t = number of years and A = amount after t years
simplifying that becomes
A = 400 (1.005)^4t
b amount after 5 years is
400 (1.005)^(4*5) = 400 (1.005)^20 = $ 441.96
