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Sliva [168]
2 years ago
8

Drag the numbers to complete the following statements.

Mathematics
2 answers:
Nitella [24]2 years ago
6 0

Answer:

Step-by-step explanation:49.5

babunello [35]2 years ago
3 0

Answer:

49.5 is the answer

Step-by-step explanation:

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Evaluate the expression 3(7 + 4)2 − 14 ÷ 7. 50 361 363 586
Kipish [7]
It appears that none of your option choices are correct,, are you sure you copied them right ? I will show you how to solve this and how I got my answer.
The first step for solving this is to add the numbers in the parenthesis.
3 × 11 × 2 - 14 ÷ 7
Divide -14 by 7.
3 × 11 × 2 - 2
Divide the first 3 numbers together.
66 - 2
Subtract the numbers together to get your final answer.
64
Let me know if you have any further questions.
:)
4 0
2 years ago
Read 2 more answers
Which part of a fraction tells how many parts it takes to make a whole? (Numerator of denominator?)
solmaris [256]
The denominator will tell how many parts it takes to make a whole


4 0
3 years ago
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Which function has a range of<br><br> f(x)≥7
amid [387]

Answer:

While it's true that quadratic functions have no domain restrictions, the range is restricted because x2 ≥ 0. The correct answer is: The domain is all real numbers and the range is all real numbers f(x) such that f(x) ≥ 7.

Step-by-step explanation:

3 0
3 years ago
Write an equation that shows the relationship 40% of 140 is x
uranmaximum [27]

Answer:

x=140times0.4

Step-by-step explanation:

then subtract your anser from 140

5 0
2 years ago
Can someone help me with this​
SashulF [63]

Answer:

\angle NRQ =85 \degree

Given:

\angle RPQ = 45 \degree \\  \angle PQR = (6x + 4)\degree \\  \angle NRQ = (15x - 5)\degree

Step-by-step explanation:

Property used: <em>An exterior angle of a triangle is equal to the sum of the opposite int</em><em>e</em><em>rior angles.</em>

<em>=  >  \angle RPQ +  \angle PQR =  \angle NRQ \\  \\  =  > 45 \degree + (6x + 4)\degree = (15x - 5)\degree \\  \\  =  > 45\degree + 6x\degree + 4\degree = 15x\degree - 5\degree \\  \\  =  > 49\degree  + 5 \degree= 15x\degree - 6x\degree \\  \\  =  > 54\degree = 9x\degree \\  \\  =  > 9x\degree = 54\degree \\  \\  =  > x\degree =  (\frac{54}{9} )\degree \\  \\  =  > x\degree = 6\degree \\  \\ Putting \: value \: of \: x \: in \:  \angle NRQ  \\   \\  =  > \angle NRQ = (15x - 5)\degree \\  \\  =  >  \angle NRQ = (15 \times 6 - 5) \degree \\  \\  =  >  \angle NRQ =85 \degree</em>

4 0
2 years ago
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