Answer:
y=-7/4x+5
Step-by-step explanation:
The line contains points at (4,-2) and (0,-5)
(y1-y2) / (x1-x2) = slope
(4,-2) =(x1,y1)
(0,-5) = (x2,y2)
(-2-5) / (4-0)
-7 / 4 = -7/4
y= -7/4x + b
plug in points for x and y to find b
-2=-7/4(4)+b
-2=-7+b
5=b
y=-7/4x+5
Answer:
7
Step-by-step explanation:
Since you did not include the figure with the circle to which you have to compare the equations, I am going to determine the center and radius of the circles represented by each of the equations.
From that, you choose that whose center is the same of your circle and the radius is the double.
The canonic equation of a circle is:
(x - a)² + (y - b)² = r²
Where a and b are the coordinates of the center (a,b) and r is the radius.
So, let's determine the center and the radius of all the equations given:
<span> A) (x – 4)² + (y – 6)² = 4
</span><span>
</span><span>
</span><span>Center (4,6),;radius = √4 = 2
</span><span>
</span><span>
</span><span>B) (x – 4)² + (y – 6)² = 16
</span><span>
</span><span>
</span><span>Center (4, 6); radius = √16 = 4
</span><span>
</span>
<span>C) (x – 6)² + (y – 4)² = 16
</span><span>
</span><span>
</span><span>Center = (6, 4); radius = √16 = 4
</span><span>
</span><span>
</span><span>D) (x – 6)² + (y – 4)² = 4
</span>
Center (6, 4); radius = √4 = 2
Step-by-step explanation:
1. Given angles are,
40°, 3x+8° , 10x+42°
Therefore, by the problem,
=> 40° + 3x+8° + 10x+42° = 180° [Angle sum property of triangle]
=> 3x + 10x = 180° - (40°+42°+8°)
=> 13x = 180° - 90°
=> 13x = 90°
<u>Hence required value of x is (90/13)°</u>
2. Given,
12x - 18° = 5x +19° [Alternate angles]
=> 12x - 5x = 19 + 18
=> 7x = 37
<u>Hence required value of x is (37/7)°</u>
3. Given,
Exterior angle 132°
So it's paired interior angle will be = 180° - 132° (linear pair) = 48°
Hence the angles we get are = 42° , 87° , 20x - 10°
Therefore, by the problem,
48° + 87° + 20x - 10° = 180° [Angle sum property of triangle]
=> 20x = 180 - 48 - 87 + 10
=> 20x = 55
=> x = 2.75
<u>Hence required value of x is </u><u>2.75</u>
