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Darina [25.2K]
3 years ago
12

Using the given equation find the missing coordinates o the points and then find the slope of the line for each equation y-2x=3;

A(...;6), B(15; ...)
Mathematics
1 answer:
dimaraw [331]3 years ago
8 0

Answer:

(1.5,6)(15,33) slope=2

Step-by-step explanation:

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Perform the indicated operation. 12/16 - 3/8
Vladimir79 [104]

Answer:

6/16

Step-by-step explanation:

12/16-3/8

12/16-6/16

6/16=3/8

3 0
4 years ago
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Geno signed up for a text messaging plan. He pays a $5.00 monthly fee and $0.04 per text message.
Marysya12 [62]

Answer:

The correct answer is [C.) 0.04r + 5.00}

Step-by-step explanation:

hope this hlps

7 0
3 years ago
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Function tables with two-step rules Fill in the table using this function rule.<br> help asap
NeTakaya

Answers:

Answer for row one:     1

Answer for row two:     11

Answer for row three:   16

Answer for row four:     36

=========================================

Work Shown:

Whatever the x value is, we multiply by 5 and subtract off 14 to get the corresponding y value. This is following the order of operations PEMDAS

------------

If x = 3, then

y = 5*x - 14

y = 5*3 - 14  ..... note how x is replaced with 3

y = 15 - 14

y = 1

This means that when x = 3, the y value is y = 1.

So 1 goes in the box in the first row.

---------------

Repeat for x = 5

y = 5*x - 14

y = 5*5 - 14

y = 25 - 14

y = 11

We have 11 as the second answer.

--------------

Repeat for x = 6

y = 5*x - 14

y = 5*6 - 14

y = 30 - 14

y = 16

The third answer is 16.

--------------

Repeat for x = 10

y = 5*x - 14

y = 5*10 - 14

y = 50 - 14

y = 36

The last answer is 36.

3 0
4 years ago
The lateral surface area of cone A is exactly 1/2 the lateral surface area of cylinder B. Cone A radius is r and height h - Cyli
Mrac [35]

The ratio of the <em>lateral surface</em> area of cone A to the <em>lateral surface</em> area of cylinder B is equal to r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}. (Correct choice: False)

<h3>What is the ratio of lateral area of cone to the lateral area of the cylinder?</h3>

In accordance with <em>space</em> geometry, the <em>lateral</em> areas of the cone and cylinder are described by the following equations:

Cone

A_{l} = \pi \cdot r \cdot \sqrt{r^{2}+h^{2}}     (1)

Cylinder

A_{l} = 2\pi\cdot r\cdot h     (2)

If we divide (2) by (1), then we have the following ratio:

r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}

The ratio of the <em>lateral surface</em> area of cone A to the <em>lateral surface</em> area of cylinder B is equal to r = \frac{1}{2}\cdot \frac{\sqrt{r^{2}+h^{2}}}{h}. (Correct choice: False)

To learn more on surface areas: brainly.com/question/2835293

#SPJ1

3 0
2 years ago
X:y=5:3 and x+y=56 work out the value of x-y
Vladimir79 [104]

x - y = 14

given the ratio x : y = 5 : 3

then let x = 5x and y = 3x, hence equation can be expressed as

5x + 3x = 56

8x = 56 ( divide both sides by 8 )

x = 7

Hence x = 5 × 7 = 35 and y = 3 × 7 = 21

Thus x - y = 35 - 21 = 14


6 0
3 years ago
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