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nekit [7.7K]
3 years ago
10

If F(x)=2x^2+3, then which of the following represent f(x+1). A.2x^2+2. B. X^2+3. C. 2x^2+4x+1. D. 2x^2+4x+5

Mathematics
1 answer:
serg [7]3 years ago
5 0
Hi,
If it is f(x)=2x²+3 and not F(x)=2x²+3 then 
Answer D.

f(x)=2x^2+3\\

f(x+1)=2(x+1)^2+3\\
=2(x^2+2x+1)+3\\
=2x^2+4x+5\\


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The ball should be aimed to the point of the wall that is about 45 degrees from the wall.
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Find the mass of the lamina that occupies the region D = {(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1} with the density function ρ(x, y) = xye
Alona [7]

Answer:

The mass of the lamina is 1

Step-by-step explanation:

Let \rho(x,y) be a continuous density function of a lamina in the plane region D,then the mass of the lamina is given by:

m=\int\limits \int\limits_D \rho(x,y) \, dA.

From the question, the given density function is \rho (x,y)=xye^{x+y}.

Again, the lamina occupies a rectangular region: D={(x, y) : 0 ≤ x ≤ 1, 0 ≤ y ≤ 1}.

The mass of the lamina can be found by evaluating the double integral:

I=\int\limits^1_0\int\limits^1_0xye^{x+y}dydx.

Since D is a rectangular region, we can apply Fubini's Theorem to get:

I=\int\limits^1_0(\int\limits^1_0xye^{x+y}dy)dx.

Let the inner integral be: I_0=\int\limits^1_0xye^{x+y}dy, then

I=\int\limits^1_0(I_0)dx.

The inner integral is evaluated using integration by parts.

Let u=xy, the partial derivative of u wrt y is

\implies du=xdy

and

dv=\int\limits e^{x+y} dy, integrating wrt y, we obtain

v=\int\limits e^{x+y}

Recall the integration by parts formula:\int\limits udv=uv- \int\limits vdu

This implies that:

\int\limits xye^{x+y}dy=xye^{x+y}-\int\limits e^{x+y}\cdot xdy

\int\limits xye^{x+y}dy=xye^{x+y}-xe^{x+y}

I_0=\int\limits^1_0 xye^{x+y}dy

We substitute the limits of integration and evaluate to get:

I_0=xe^x

This implies that:

I=\int\limits^1_0(xe^x)dx.

Or

I=\int\limits^1_0xe^xdx.

We again apply integration by parts formula to get:

\int\limits xe^xdx=e^x(x-1).

I=\int\limits^1_0xe^xdx=e^1(1-1)-e^0(0-1).

I=\int\limits^1_0xe^xdx=0-1(0-1).

I=\int\limits^1_0xe^xdx=0-1(-1)=1.

No unit is given, therefore the mass of the lamina is 1.

3 0
3 years ago
Find the area of the region bounded by the curves y = sin^-1(x/6), y = 0, and x = 6 obtained by integrating with respect to y. Y
Nezavi [6.7K]
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Answer:

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Read 2 more answers
The wholesale price for a shirt is $5.50. A certain department store marks up the wholesale price by 40%. Find the price of the
Kazeer [188]

Answer:

$7.7

Step-by-step explanation:

Hello, I can help you with this

you can solve this by using a simple rule of three.

Step 1

define

if the wholesale price for a shirt is $5.50,it is 100 percent

$5.50⇔100%

the new price(x) is 40% more than the original, it means 140%

x  ⇔ 140%

the relation is

\frac{5.5}{100}= \frac{x}{140}\\

Step 2

solve for x(isolate x)

\frac{5.5}{100}= \frac{x}{140}\\x=\frac{5.5*140}{100}\\x=7.7

the price of the shirt in the department store is $7.7

Have a nice day.

7 0
3 years ago
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