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Shtirlitz [24]
3 years ago
5

Determine if the equation y = 2/5 x − 4 y=25x-4 represents a proportional relationship. If so, determine the constant of proport

ionality.
Mathematics
1 answer:
Vilka [71]3 years ago
8 0

Answer:

The linear equation represents a proportional relationship and its constant of proportionality is k = \frac{2}{5}.

Step-by-step explanation:

A proportional relationship exists when the following relationship is observed:

u = k\cdot v

Where:

u - Dependent variable.

v - Independent variable.

k - Proportionality constant.

If y =\frac{2}{5}\cdot x - 4 and v = x and u = y+4, the following expresion is found:

y = \frac{2}{5}\cdot x -4

y + 4 = \frac{2}{5}\cdot x

u = \frac{2}{5}\cdot v

The linear equation represents a proportional relationship and its constant of proportionality is k = \frac{2}{5}.

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Answer:

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Step-by-step explanation:

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Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


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3 years ago
Which values of P and Q does the following equation have infinitely many solutions?
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Any value as long as P = Q

For the equation to have infinitely many solutions, we require both sides of the equation to have exactly the same terms.

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(Please help!!) Solve: x2+6x+9
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