Write the equation of the line parallel to the line 3x + 5y = 7 and passes through the point (-1, 3) in standard form. Please he

Question

2 years ago

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1 answer:

makkiz [27] · Answer 1 · 2022-09-16T03:19:32+03:00

Answer:

Step-by-step explanation:

3x + 5y = 7 {subtract 3x from both sides}

5y = -3x + 7 {divide both sides by 5}

y = -³/₅x + ⁷/₅ ← slope-intercept form

y=m₁x+b₁ ║ y=m₂x+b₂ ⇔ m₁ = m₂

{Two lines are parallel if their slopes are equal}

y = -³/₅x + ⁷/₅ ⇒ m₁ = -³/₅ ⇒ m₂ = -³/₅

(-1, 3) ⇒ x₁ = -1, y₁ = 3

The point-slope form:

y - 3 = -³/₅(x - (-1))

y - 3 = -³/₅(x + 1) {myltiply both sides by 5}

5y - 15 = -3x - 3 {add 3x to both sides}

3x + 5y - 15 = - 3 {add 15 to both sides}