Answer:
225.78 grams
Step-by-step explanation:
To solve this question, we would be using the formula
P(t) = Po × 2^t/n
Where P(t) = Remaining amount after r hours
Po = Initial amount
t = Time
In the question,
Where P(t) = Remaining amount after r hours = unknown
Po = Initial amount = 537
t = Time = 10 days
P(t) = 537 × 2^(10/)
P(t) = 225.78 grams
Therefore, the amount of iodine-131 left after 10 days = 225.78 grams
Answer:
x= -6, y= 10
Step-by-step explanation:
x= y + 4
2x = 3y - 2
If we replace "x" with "y+4" in the second equation we get:
2(y+4) = 3y - 2
2y + 8 = 3y - 2
2y - 3y = -2-8
-y = -10
y = 10
Now we can go back to the first equation and solve for x:
x = y + 4
x = 10 + 4 = 14
you need help with sum
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