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Semenov [28]
3 years ago
12

What THREE integers have a sum of 300?

Mathematics
2 answers:
quester [9]3 years ago
8 0

Answer:

Here we will use algebra to find three consecutive integers whose sum is 300. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 300. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 300

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 300

3X + 3 = 300

3X + 3 - 3 = 300 - 3

3X = 297

3X/3 = 297/3

X = 99

Which means that the first number is 99, the second number is 99 + 1 and the third number is 99 + 2. Therefore, three consecutive integers that add up to 300 are 99, 100, and 101.

99 + 100 + 101 = 300

We know our answer is correct because 99 + 100 + 101 equals 300 as displayed above.

Step-by-step explanation:

Bond [772]3 years ago
5 0

Answer:

99, 100, and 101

Step-by-step explanation:

Just add these numbers

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Omar has 3 1/14 cups of dough to make dumplings.If he uses 3/16 cup of dough for each dumpling,how many whole dumplings can Omar
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Answer:

Omar can make 16 dumplings with some dough to spare

Step-by-step explanation:

you should convert each value to have the same denominator to make the equation easier

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so the total 43/14 needs to be divided by 3/16

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6 0
3 years ago
What is the simplified form of x+2/x^2-3x-10 * x-3/x^2+x-12
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\frac{x + 2}{ {x}^{2} + 2x - 5x - 10 }  \times  \frac{x - 3}{ {x}^{2} + 4x - 3x - 12 }
\frac{x + 2}{x(x + 2) - 5(x + 2)}  \times  \frac{x - 3}{x(x + 4) - 3(x + 4)}
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and basically that's the "answer", but you can simplify more.

\frac{1}{ {x}^{2}  + 4x - 5x - 20}
\frac{1}{ {x}^{2} - x - 20 }
Hope that's helpful
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3 years ago
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Hope this answers the question. Have a nice day.
6 0
3 years ago
Read 2 more answers
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