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2 years ago

What THREE integers have a sum of 300?

Mathematics

2 answers:

quester [9]2 years ago

8 0

Answer:

Here we will use algebra to find three consecutive integers whose sum is 300. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 300. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 300

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 300

3X + 3 = 300

3X + 3 - 3 = 300 - 3

3X = 297

3X/3 = 297/3

X = 99

Which means that the first number is 99, the second number is 99 + 1 and the third number is 99 + 2. Therefore, three consecutive integers that add up to 300 are 99, 100, and 101.

99 + 100 + 101 = 300

We know our answer is correct because 99 + 100 + 101 equals 300 as displayed above.

Step-by-step explanation:

Bond [772]2 years ago

5 0

Answer:

99, 100, and 101

Step-by-step explanation:

Just add these numbers

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PLEASE HELP!!!

pogonyaev

Step-by-step explanation:

Part A:

Let $m$ be the number of mittens and $s$ be the number of scarves. Then we have the inequalities:

$s+m\leq 30.$ This says Nivyana and Ana cannot make more than 30 scarves

$50s+25m\geq 1000.$ This says that Nivyana and Ana have to earn at least $1000.

Part B:

The graph is attached.

Notice that the graphs of the inequalities are solid lines, this just means that the points on these lines included to the solutions of each inequality.

The darker shaded region and the solid lines bounding it, are the solutions to the inequalities because that's where the values common to both inequalities are found.

Part C:

From the graph we get two possible solutions:

15 scarves & 10 mittens

25 scarves & 5 mittens.

These two points lie on the solid lines that bound the darker shaded region (I picked those points to stress that the lines bounding the dark region are also solutions.)