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Semenov [28]
3 years ago
12

What THREE integers have a sum of 300?

Mathematics
2 answers:
quester [9]3 years ago
8 0

Answer:

Here we will use algebra to find three consecutive integers whose sum is 300. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 300. Therefore, you can write the equation as follows:

(X) + (X + 1) + (X + 2) = 300

To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 300

3X + 3 = 300

3X + 3 - 3 = 300 - 3

3X = 297

3X/3 = 297/3

X = 99

Which means that the first number is 99, the second number is 99 + 1 and the third number is 99 + 2. Therefore, three consecutive integers that add up to 300 are 99, 100, and 101.

99 + 100 + 101 = 300

We know our answer is correct because 99 + 100 + 101 equals 300 as displayed above.

Step-by-step explanation:

Bond [772]3 years ago
5 0

Answer:

99, 100, and 101

Step-by-step explanation:

Just add these numbers

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Solve the system of equations.
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Answer:

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Step-by-step explanation:

Let's solve this system of equations using the elimination method.

Start by labelling the two equations.

5x -y= 5 -----(1)

5x² -y= 5 -----(2)

(2) -(1):

5x² -y -(5x -y)= 5 -5

Expand:

5x² -y -5x +y= 0

5x² -5x= 0

Factorise:

5x(x -1)= 0

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Now that we have found the x values, we can substitute them into either equations to solve for y.

Substitute into (1):

5(0) -y= 5 or 5(1) -y= 5

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2 years ago
Determine the common ratio r of a geometric sequence with first term 5 and<br> fourth term -40.
viva [34]

Answer:

Step-by-step explanation:

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Step-by-step explanation:

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After a bride has interviewed 7 DJs to play at her wedding, her fiance tells her she needs to narrow it down to 4 DJs. In how ma
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Step-by-step explanation:

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To\ pick = 4

Required

Determine the number of rankings

The term "ranking" as used in this question implies permutation and the required is calculated using:

^nP_r = \frac{n!}{(n-r)!}

Where

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^nP_r = \frac{n!}{(n-r)!}

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