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bonufazy [111]
3 years ago
7

What is the quotient of 8,595 ÷ 24?

Mathematics
2 answers:
fomenos3 years ago
7 0
The quotient is the result of a division. thus: 8595/24=358.125
lana [24]3 years ago
4 0
The answer is 358 R3

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500 grams of tomatoes cost £1.76 how much will 1.75kg cost??
ValentinkaMS [17]
500 grams equals 0.50 kg so multiply 1.76 3 times to get 5.28, then divide 1.76 by 2 to get .88 add the two together to get 6.16
3 0
3 years ago
Original price: $95; Markdown: 10%...Show your work
Rasek [7]
$95.00 minus $9.50 equals $85.50
4 0
3 years ago
Find the average rate of change of f(x)=2x^2-7x from x=2 to x=6
scoundrel [369]

Answer:

Step-by-step explanation:

The average rate of change of a function f between a and b (a< b) is :

R =[f(b)-f(a)] ÷ (a-b)

●●●●●●●●●●●●●●●●●●●●●●●●

Let R be the average rate of change of this function

f(6) = 2×6^2 - 7×6 = 72-42 = 30

f(2) = 2×2^2 - 7×2 = 8-14 = -6

R = [f(6) - f(2)]÷ (6-2)

R = [30-(-6)] ÷ 4

R = -36/4

R = -9

■■■■■■■■■■■■■■■■■■■■■■■■■

The average rate of change of this function is -9

8 0
3 years ago
Read 2 more answers
50 points! Dustin and Melanie are playing a game, where two standard, six-sided number cubes are rolled, and the sum of their ou
Assoli18 [71]
Melanie made a better decision


Hope I helped!

Let me know if you need anything else!

<span>~ Zoe (Rank:'Genius')</span>
5 0
3 years ago
Read 2 more answers
Swimming speed of salmon. The graph is showed below shows the influence of the temperature T on the maximum sustainable swimming
Doss [256]

Answer:

Here we have the relation between the speed of the salmon and the temperature.

a) the relation dS/dT tell us how the speed of the salmon changes as the temperature changes, and the units should be (if speed is m/s and temperature is in °C )

[dS/dT ] = [m/s*°C ].

b) I can not do a draw of the figure, but i can give a aproximation.

For T = 18°C, we can see that we are around the maximum of the curve, this means that around this point we will find the zero in the first derivate.

then S'(18) ≈ 0 m/s*°C

this means that around this point the changes are small.

for T = 10°C

Around this region, we can see almost a linear behavior.

so we can take a range of +-2°C

S(12°C) = 25m/s

S(8°C) = 20m/s

then the slope can be obtained using the relation:

S = (Y2 - Y1)/(X2 - X1) where this is the slope for the line that goes trough the pairs. (X1, Y1) and (X2, Y2)

S = (25 - 20)/(12 - 8) = 5/4

then we have that S´(10°C) ≈ 5/4 m/s*°C

Those two results are approximations, you may find better approximations by doing this with a ruler and drawing the tangents.

5 0
3 years ago
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