How do you solve (a+5)^2=25 using quadratics

Mathematics

2 answers:

Leona [35]3 years ago

6 0

Answer:

a = 0 ; a = -10

Step-by-step explanation:

a squared number give as result a positive number, either if it is positive or negative

we have to find two numbers whose square is 25: these numbers are 5 and -5

a+5 = 5

a = 0

a+5 = -5

a = -10

agasfer [191]3 years ago

5 0

Answer:

(a+5)^2=25 means a^2+5^2=25, a^2=25-25 then a^2=√0, a=0

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If:

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Firstly we have to rearrange the right side of equation (2) in terms of $x^{2}+4$ , factorizing by the common factor:

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Then, we can substitute $x^{2}+4$ by $a$ :

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And set it equal to zero:

$a^{2}-12a+32=0$ >>>>This is the resulting equation

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In this case, the variable is $a$ and the number that multiplies the variable (the coefficient) is $-12$ , whereas the constant (which is the term with no variable) is $32$