Answer:
B. 3.
Step-by-step explanation:
OK lets try again.
The slope of the secant = slope of the tangent at a certain point ( The Mean Value Theorem).
Slope of the secant = f(5) - f(2) / (5 - 2)
= [(25-3) / (5-1) - (4-3) / (2-1)] / 3
= (22/4 - 1) / 3
= 9/2 / 3
= 9/6
= 3/2.
The derivative at c = the slope of the tangent at c.
Finding the derivative:
f'(x) = [2x(x - 1) - (x^2 - 3) ]/ (x - 1)^2 (where x = c).
= (x^2 - 2x + 3)/ (x - 1)^2 = the slope.
So equating the slopes:
(x^2 - 2x + 3) / (x - 1)^2 = 3/2
2x^2 - 4x + 6 = 3x^2 - 6x + 3
x^2 - 2x - 3 = 0
(x - 3)(x + 1) = 90
x = 3 , -1
x can't be -1 because we are working between the values 2 and 5 so
x = c = 3.
The formula for a regular polygon, which this one is, is A = 1/2 ap where a is the apothem and p is the perimeter. 20.8 * 7 = 145.6 which is the perimeter, so now just multiply by 21.6 and .5. 145.6 * 21.6 * .5 = 1572.48, or B above.
Answer:y=4x -7
Step-by-step explanation:
The slope intercept form is: y= mx + b
Y+3 = 4(x-1) step one distribute 4
Y+3= 4x - 4 step two subtract 3 from both sides
Y=4x -7
Answer:
-6x-16
Step-by-step explanation:
