Answer:
A batch of 20 semiconductor chips is inspected by choosing a sample of 3 chips. Assume 10 of the chips do not conform to customer requirements.
a) Number of different samples = 20C3 = 
=1140
b) 2 good and one bad chip
Number of samples = 10C2 * 10C1 = 45 * 10 =450
c) 2 good 1 bad + 1 good 2 bad + 3 bad
Number of samples = 10C2 * 10C1 + 10C1 * 10C2 + 10C3
= 
Answer:
483 ft²
Step-by-step explanation:
2(7x7)= 98
3(5x12)=180
2(12x5)=120
2(5x5)= 50
1(7x5) = <u> 35 </u>
483
Answer:
:)Step-by-step explanation:
Answer:
He made approximately 32 free throws.
Step-by-step explanation:
Assuming that there's a typo in the question and that he made 57% of his attempted free throws, then we can solve it as shown below:
We can apply a rule of three in order to calculate the number of free throws he made. This is done as follows:
56 free throws -> 100%
x free throws -> 57%
56/x = 100/57
100*x = 57*56
x = 57*56/100 = 31.92
It can also be solved by transforming the percentage in a fraction such as 57% = 57/100 and then multiplying it by the total attempts.
free throws made = 56*57/100 = 31.92
He made approximately 32 free throws.
