-1 C, that's the only logical answer I can think of. Or does it have to be in F?
Answer:
Step-by-step explanation:
P(-2,-1) and Q(4,3)
average of x-coordinates = (-2+4)/2 = 1
average of y-coordinates = (-1+3)/2 = 1
midpoint of PQ: (1,1)
distance between midpoint and Q = √((4-1)²+(3-1)²) = √13
(x-1)² + (y-1)² = 13
Answer:
The coordinates of H′ are (-2,0).
Step-by-step explanation:
It is given that square EFGH stretches vertically by a factor of 2.5 with respect to the x-axis to create rectangle E′F′G′H′.
If a figure stretches vertically by a factor of 2.5 with respect to the x-axis, then the x-coordinates remains same and the points which lie on the axis are also remains the same after stretch.
It is given that the coordinates of H are (-2,0). This point lie on the x-axis, therefore it will remains the same after stretch.
Therefore the coordinates of H′ are (-2,0).
Answer:
Width is 2 if that's what you were looking for.
Step-by-step explanation:
I'm guessing it's a rectangle and you want the width?
22-9-9=2w
2w=4
The width is 2
