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il63 [147K]
3 years ago
8

Find the distance between the two points rounding to the nearest tenth (if necessary).

Mathematics
1 answer:
iris [78.8K]3 years ago
5 0

Step-by-step explanation:

Distance between (−3,6) and (−9,−2):

(x_1, y_1)

= coordinates of the first point

= (-3,6)

(x_2, y_2)

= coordinates of the second point

= (-9,-2)

d  =  \sqrt{(x_2 -  {x _1) }^{2} + (y_2 -  {y _1) }^{2}}

d =  \sqrt{ (- 9 - ( - 3) {)}^{2}  + ( - 2 + 6 {)}^{2} }

d \:  =  \sqrt{ (- 6 {)}^{2}  +( 4 {)}^{2} }

d  =  \sqrt{36 + 16}

d  =  \sqrt{52}

d =  \sqrt{13 \times 2 \times 2}

d = 2 \sqrt{13}

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Answer:

the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

Step-by-step explanation:

Let assume that n should represent the number of the students

SO, \bar x can now be the sample mean of number of students  in GPA's

To obtain n such that P( \bar x \leq 2.3 ) \leq .04

⇒ P( \bar x \geq 2.3 ) \geq .96

However ;

E(x) = \int\limits^4_2 Dx (2+e^{-x} ) 4x = D  \\ \\ = D(e^{-x} (e^xx^2 - x-1 ) ) ^D_2 = 12.314 D

E(x^2) = D\int\limits^4_2 (2+e^{-x})dx \\ \\ = \dfrac{D}{3}[e^{-4} (2e^x x^3 -3x^2 -6x -6)]^4__2}}= 38.21 \ D

Similarly;

D\int\limits^4_2(2+ e^{-x}) dx = 1

⇒ D*(2x-e^{-x} ) |^4_2 = 1

⇒ D*4.117 = 1

⇒ D= \dfrac{1}{4.117}

\mu = E(x) = 2.991013 ; \\ \\ E(x^2) = 9.28103

∴  Var (x)  = E(x^2) - E^2(x) \\ \\  = .3348711

Now; P(\bar \geq 2.3) = P( \bar x - 2.991013 \geq 2.3 - 2.991013) \\ \\ = P( \omega  \geq .691013)  \ \ \ \  \ \ \ \ \ \ (x = E(\bar x ) - \mu)

Using Chebysher one sided inequality ; we have:

P(\omega \geq -.691013) \geq \dfrac{(.691013)^2}{Var ( \omega) +(.691013)^2}

So; (\omega = \bar x - \mu)

⇒ E(\omega ) = 0 \\ \\ Var (\omega ) = \dfrac{Var (x_i)}{n}

∴ P(\omega \geq .691013) \geq \dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2}

To determine n; such that ;

\dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2} \geq 0.96 \\ \\ \\ (.691013)^2(1-.96) \geq \dfrac{-3348711*.96}{n}

⇒ n \geq \dfrac{.3348711*.96}{.04*(.691013)^2}

n \geq 16.83125

Thus; we can conclude that; the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

5 0
3 years ago
in an election between two candidates one got 55% of the total valid votes 20% votes were invalid if the total number of votes w
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Answer:

25%- 1875 Votes

<em>7500 x 0.55 = 4125  (</em><em>first candite valid votes</em><em>)</em>

<em>7500 x 0.20 = 1500 (</em><em>invalid</em><em>)</em>

<em>first candite valid votes</em><em> </em><em>(</em><em>55</em><em>) + invalid votes (</em><em>20</em><em>) = 75% of total votes </em>

<em>first candite valid votes</em><em> </em><em>(</em><em>4125</em><em>) + invalid votes (</em><em>1500 </em><em>) = 5625 of total votes </em>

<em />

<em>100 (</em><em>total</em><em> </em><em>percent of votes</em><em>) - 75 (</em><em>total percent of votes</em><em>) = 25% Votes Left</em>

<em>7500 (</em><em>total</em><em> </em><em>number of votes</em><em>) - 5625 (</em><em>total number of votes</em><em>) = 1875 Votes Left</em>

<em>7500 x 0.25 = 1875 (</em><em>valid votes for the other candite</em><em>)</em>

<em>          </em>

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3 years ago
Help please I don’t get it
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Answer:

3/8

Step-by-step explanation:

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3 years ago
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Brainliest to first right, along with 5 stars, and a thanks, lol:)
vlada-n [284]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
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